Find Logarithm Value: We need to find the value of log_(16)8. This means we are looking for the exponent that 16 must be raised to in order to get 8.Express in Powers of 2: Since 16 is 2 raised to the 4th power (16 = 2^4), we can express 8 as a power of 2 as well, which is 2^3 (since 8 = 2^3).Rewrite in Base 2: Now we can rewrite the logarithm in terms of base 2: log_(16)8 = log_(2^4)(2^3).Simplify Using Property: Using the property of logarithms that log_(b^k)(a^k) = log_b(a), we can simplify the expression to log_(2^4)(2^3) = (3/4) * log_(2)(2).Evaluate Logarithm: Since log_(2)(2) is 1 (because 2 raised to the power of 1 is 2), we can simplify further: (3/4) * log_(2)(2) = (3/4) * 1.Final Result: Multiplying (3/4) by 1 gives us 3/4. So, log_(16)8 = 3/4.

Grade 8

Relationship between squares and square roots

Full solution

\log _{16} 8=

Find Logarithm Value: We need to find the value of $\log_{16}8$ . This means we are looking for the exponent that $16$ must be raised to in order to get $8$ .
Express in Powers of $2$ : Since $16$ is $2$ raised to the $4$ th power ( $16 = 2^4$ ), we can express $8$ as a power of $2$ as well, which is $2^3$ (since $8 = 2^3$ ).
Rewrite in Base $2$ : Now we can rewrite the logarithm in terms of base $2$ : $\log_{16}8 = \log_{2^4}(2^3)$ .
Simplify Using Property: Using the property of logarithms that $\log_{b^k}(a^k) = \log_b(a)$ , we can simplify the expression to $\log_{2^4}(2^3) = \left(\frac{3}{4}\right) \cdot \log_{2}(2)$ .
Evaluate Logarithm: Since $\log_{2}(2)$ is $1$ (because $2$ raised to the power of $1$ is $2$ ), we can simplify further: $(\frac{3}{4}) \times \log_{2}(2) = (\frac{3}{4}) \times 1$ .
Final Result: Multiplying $(\frac{3}{4})$ by $1$ gives us $\frac{3}{4}$ . So, $\log_{16}8 = \frac{3}{4}$ .