Let g(x)=−3sin(x−2)x.Select the correct description of the one-sided limits of g at x=2.Choose 1 answer:(A)limx→2+g(x)=+∞ and limx→2−g(x)=+∞(B)limx→2+g(x)=+∞ and limx→2−g(x)=−∞(c)limx→2+g(x)=−∞ and limx→2−g(x)=+∞(D)limx→2+g(x)=−∞ and limx→2−g(x)=−∞
Q. Let g(x)=−3sin(x−2)x.Select the correct description of the one-sided limits of g at x=2.Choose 1 answer:(A)limx→2+g(x)=+∞ and limx→2−g(x)=+∞(B)limx→2+g(x)=+∞ and limx→2−g(x)=−∞(c)limx→2+g(x)=−∞ and limx→2−g(x)=+∞(D)limx→2+g(x)=−∞ and limx→2−g(x)=−∞
Analyze Function Near x=2: Analyze the function g(x) near x=2. We have the function g(x)=−3sin(x−2)x. To find the one-sided limits as x approaches 2, we need to consider the behavior of the sine function near x=2.
Limit from the Right: Consider the limit from the right, limx→2+g(x). As x approaches 2 from the right, (x−2) approaches 0 from the right, and sin(x−2) approaches sin(0) from the right, which is 0. Since the sine function is continuous and smooth, just to the right of 0, the sine is positive. Therefore, sin(x−2) will be a small positive number, making x0 a small positive number. The numerator x1 will be a small negative number since x is just slightly larger than 2. Dividing a small negative number by a small positive number yields a large negative number. Hence, x4.
Limit from the Left: Consider the limit from the left, limx→2−g(x). As x approaches 2 from the left, (x−2) approaches 0 from the left, and sin(x−2) approaches sin(0) from the left, which is 0. Since the sine function is continuous and smooth, just to the left of 0, the sine is negative. Therefore, sin(x−2) will be a small negative number, making x0 a small negative number. The numerator x1 will be a small negative number since x is just slightly less than 2. Dividing a small negative number by another small negative number yields a large positive number. Hence, x4.
More problems from Compare linear, exponential, and quadratic growth