Let g(x)=(x−3)22.Select the correct description of the one-sided limits of g at x=3.Choose 1 answer:(A)limx→3+g(x)=+∞ and limx→3−g(x)=+∞(B)limx→3+g(x)=+∞ and limx→3−g(x)=−∞(C)limx→3+g(x)=−∞ and limx→3−g(x)=+∞(D)limx→3+g(x)=−∞ and limx→3−g(x)=−∞
Q. Let g(x)=(x−3)22.Select the correct description of the one-sided limits of g at x=3.Choose 1 answer:(A)limx→3+g(x)=+∞ and limx→3−g(x)=+∞(B)limx→3+g(x)=+∞ and limx→3−g(x)=−∞(C)limx→3+g(x)=−∞ and limx→3−g(x)=+∞(D)limx→3+g(x)=−∞ and limx→3−g(x)=−∞
Analyze function behavior: Analyze the function g(x)=(x−3)22 to understand its behavior near x=3. The function is a rational function with a denominator that approaches zero as x approaches 3. Since the numerator is a positive constant (2), the sign of g(x) will depend on the sign of the denominator.
Limit from the right: Consider the limit as x approaches 3 from the right (x→3+).As x gets closer to 3 from the right, (x−3)2 is always positive because squaring a real number always gives a positive result. As the denominator approaches zero, the value of g(x) becomes very large. Therefore, the limit from the right is positive infinity.
Limit from the left: Consider the limit as x approaches 3 from the left (x→3−).As x gets closer to 3 from the left, (x−3)2 is still always positive for the same reason as in Step 2. As the denominator approaches zero, the value of g(x) becomes very large. Therefore, the limit from the left is also positive infinity.
Combine results: Combine the results from Step 2 and Step 3 to determine the one-sided limits of g(x) at x=3. Since both one-sided limits are positive infinity, the correct description of the one-sided limits of g at x=3 is: limx→3+g(x)=+∞ and limx→3−g(x)=+∞.
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