Let f(x)=5sin(x+1)x.Select the correct description of the one-sided limits of f at x=−1.Choose 1 answer:(A)limx→−1+f(x)=+∞ and limx→−1−f(x)=+∞(B)limx→−1+f(x)=+∞ and limx→−1−f(x)=−∞(C)limx→−1+f(x)=−∞ and limx→−1−f(x)=+∞(D)limx→−1+f(x)=−∞ and limx→−1−f(x)=−∞
Q. Let f(x)=5sin(x+1)x.Select the correct description of the one-sided limits of f at x=−1.Choose 1 answer:(A)limx→−1+f(x)=+∞ and limx→−1−f(x)=+∞(B)limx→−1+f(x)=+∞ and limx→−1−f(x)=−∞(C)limx→−1+f(x)=−∞ and limx→−1−f(x)=+∞(D)limx→−1+f(x)=−∞ and limx→−1−f(x)=−∞
Analyze Function Behavior: Analyze the function near the point of interest.We are interested in the behavior of the function f(x)=5sin(x+1)x as x approaches −1. To understand the behavior of the function near x=−1, we need to look at the values of the sine function near x=−1.
Evaluate Sine Function: Evaluate the sine function at the point of interest.We need to evaluate sin(x+1) as x approaches −1. When x=−1, x+1=0, and we know that sin(0)=0. This means that as x approaches −1, the denominator of our function approaches 0.
Determine Sine Sign: Determine the sign of the sine function just before and just after x=−1. Just before x=−1 (as x approaches −1 from the left), x+1 is slightly negative, and since the sine function is continuous and smooth, sin(x+1) will be slightly negative. Just after x=−1 (as x approaches −1 from the right), x+1 is slightly positive, and sin(x+1) will be slightly positive.
Calculate One-Sided Limits: Determine the one-sided limits using the sign of the sine function.As x approaches −1 from the left, sin(x+1) is negative, and since the numerator x is also negative, the fraction5sin(x+1)x will be positive. Therefore, limx→−1−f(x)=+∞.As x approaches −1 from the right, sin(x+1) is positive, and since the numerator x is negative, the fraction 5sin(x+1)x will be negative. Therefore, −11.
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