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Let 
f(x)=(x)/(1-cos(x-2)).
Select the correct description of the one-sided limits of 
f at 
x=2.
Choose 1 answer:
(A) 
lim_(x rarr2^(+))f(x)=+oo and 
lim_(x rarr2^(-))f(x)=+oo
(B) 
lim_(x rarr2^(+))f(x)=+oo and 
lim_(x rarr2^(-))f(x)=-oo
(C) 
lim_(x rarr2^(+))f(x)=-oo and 
lim_(x rarr2^(-))f(x)=+oo
(D) 
lim_(x rarr2^(+))f(x)=-oo and 
lim_(x rarr2^(-))f(x)=-oo

Let f(x)=x1cos(x2) f(x)=\frac{x}{1-\cos (x-2)} .\newlineSelect the correct description of the one-sided limits of f f at x=2 x=2 .\newlineChoose 11 answer:\newline(A) limx2+f(x)=+ \lim _{x \rightarrow 2^{+}} f(x)=+\infty and limx2f(x)=+ \lim _{x \rightarrow 2^{-}} f(x)=+\infty \newline(B) limx2+f(x)=+ \lim _{x \rightarrow 2^{+}} f(x)=+\infty and limx2f(x)= \lim _{x \rightarrow 2^{-}} f(x)=-\infty \newline(C) limx2+f(x)= \lim _{x \rightarrow 2^{+}} f(x)=-\infty and limx2f(x)=+ \lim _{x \rightarrow 2^{-}} f(x)=+\infty \newline(D) limx2+f(x)= \lim _{x \rightarrow 2^{+}} f(x)=-\infty and limx2f(x)= \lim _{x \rightarrow 2^{-}} f(x)=-\infty

Full solution

Q. Let f(x)=x1cos(x2) f(x)=\frac{x}{1-\cos (x-2)} .\newlineSelect the correct description of the one-sided limits of f f at x=2 x=2 .\newlineChoose 11 answer:\newline(A) limx2+f(x)=+ \lim _{x \rightarrow 2^{+}} f(x)=+\infty and limx2f(x)=+ \lim _{x \rightarrow 2^{-}} f(x)=+\infty \newline(B) limx2+f(x)=+ \lim _{x \rightarrow 2^{+}} f(x)=+\infty and limx2f(x)= \lim _{x \rightarrow 2^{-}} f(x)=-\infty \newline(C) limx2+f(x)= \lim _{x \rightarrow 2^{+}} f(x)=-\infty and limx2f(x)=+ \lim _{x \rightarrow 2^{-}} f(x)=+\infty \newline(D) limx2+f(x)= \lim _{x \rightarrow 2^{+}} f(x)=-\infty and limx2f(x)= \lim _{x \rightarrow 2^{-}} f(x)=-\infty
  1. Analyze Function Behavior: Analyze the function near the point of interest.\newlineWe are interested in the behavior of the function f(x)=x1cos(x2)f(x) = \frac{x}{1 - \cos(x - 2)} as xx approaches 22. Specifically, we want to know the one-sided limits as xx approaches 22 from the left (x2x \to 2^{-}) and from the right (x2+x \to 2^{+}).
  2. Consider Denominator Behavior: Consider the behavior of the denominator as xx approaches 22. The denominator of f(x)f(x) is 1cos(x2)1 - \cos(x - 2). As xx approaches 22, x2x - 2 approaches 00. The cosine of 00 is 11, so the denominator approaches 2200. We need to determine the sign of the denominator as xx approaches 22 from the left and right to understand the behavior of f(x)f(x).
  3. Sign of Denominator (Left): Determine the sign of the denominator as xx approaches 22 from the left.\newlineAs xx approaches 22 from the left (x2x \to 2^{-}), x2x - 2 is slightly negative. The cosine function is even, so cos(x2)\cos(x - 2) is the same as cos(2x)\cos(2 - x). Since 2x2 - x is slightly positive when xx is just less than 22, and the cosine function is decreasing in the interval 2211, cos(2x)\cos(2 - x) will be slightly less than 2233. Therefore, 2244 will be slightly positive, and the denominator will approach 2255 from the positive side. This means that 2266 will approach positive infinity.
  4. Sign of Denominator (Right): Determine the sign of the denominator as xx approaches 22 from the right.\newlineAs xx approaches 22 from the right (x2(+)x \to 2^{(+)}), x2x - 2 is slightly positive. Since the cosine function is even, cos(x2)\cos(x - 2) will be slightly less than 11 for the same reasons as in Step 33. Therefore, 1cos(x2)1 - \cos(x - 2) will be slightly positive, and the denominator will approach 00 from the positive side. This means that 2200 will approach positive infinity.
  5. Combine Results: Combine the results from Steps 33 and 44 to answer the question.\newlineAs xx approaches 22 from both the left and the right, the denominator of f(x)f(x) approaches 00 from the positive side, causing f(x)f(x) to approach positive infinity in both cases. Therefore, the correct description of the one-sided limits of ff at x=2x = 2 is:\newlinelimx2+f(x)=+\lim_{x \to 2^{+}} f(x) = +\infty and limx2f(x)=+\lim_{x \to 2^{-}} f(x) = +\infty.

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