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Let 
f be a continuous function on the closed interval 
[1,5], where 
f(1)=1 and 
f(5)=-3.
Which of the following is guaranteed by the Intermediate Value Theorem?
Choose 1 answer:
(A) 
f(c)=-2 for at least one 
c between 1 and 5
(B) 
f(c)=-2 for at least one 
c between -3 and 1
(C) 
f(c)=2 for at least one 
c between 1 and 5
(D) 
f(c)=2 for at least one 
c between -3 and 1

Let f f be a continuous function on the closed interval [1,5] [1,5] , where f(1)=1 f(1)=1 and f(5)=3 f(5)=-3 .\newlineWhich of the following is guaranteed by the Intermediate Value Theorem?\newlineChoose 11 answer:\newline(A) f(c)=2 f(c)=-2 for at least one c c between 11 and 55\newline(B) f(c)=2 f(c)=-2 for at least one c c between 3-3 and 11\newline(C) f(c)=2 f(c)=2 for at least one c c between 11 and 55\newline(D) f(c)=2 f(c)=2 for at least one c c between 3-3 and 11

Full solution

Q. Let f f be a continuous function on the closed interval [1,5] [1,5] , where f(1)=1 f(1)=1 and f(5)=3 f(5)=-3 .\newlineWhich of the following is guaranteed by the Intermediate Value Theorem?\newlineChoose 11 answer:\newline(A) f(c)=2 f(c)=-2 for at least one c c between 11 and 55\newline(B) f(c)=2 f(c)=-2 for at least one c c between 3-3 and 11\newline(C) f(c)=2 f(c)=2 for at least one c c between 11 and 55\newline(D) f(c)=2 f(c)=2 for at least one c c between 3-3 and 11
  1. Apply Theorem to Function: The Intermediate Value Theorem states that if ff is a continuous function on a closed interval [a,b][a, b] and NN is any number between f(a)f(a) and f(b)f(b), then there exists at least one cc in the interval (a,b)(a, b) such that f(c)=Nf(c) = N. We need to apply this theorem to the given function ff.
  2. Evaluate Function Endpoints: Since f(1)=1f(1) = 1 and f(5)=3f(5) = -3, we know that the function values at the endpoints of the interval [1,5][1, 5] are 11 and 3-3, respectively. The Intermediate Value Theorem will apply to any value NN that lies between 11 and 3-3.
  3. Determine Guaranteed Value: Looking at the answer choices, we need to determine which value of NN is guaranteed to have a corresponding cc in the interval (1,5)(1, 5) such that f(c)=Nf(c) = N.
  4. Analyze Choice (A): Choice (A) suggests that f(c)=2f(c) = -2 for some cc between 11 and 55. Since 2-2 is between 11 and 3-3, the Intermediate Value Theorem guarantees that there is at least one cc in the interval (1,5)(1, 5) for which f(c)=2f(c) = -2.
  5. Reject Choice (B): Choice (B) is incorrect because it refers to a cc between 3-3 and 11, which is outside the interval [1,5][1, 5] we are considering.
  6. Reject Choice (C): Choice (C) suggests that f(c)=2f(c) = 2 for some cc between 11 and 55. However, since 22 is not between 11 and 3-3, the Intermediate Value Theorem does not guarantee a cc in the interval (1,5)(1, 5) such that f(c)=2f(c) = 2.
  7. Reject Choice (D): Choice (D) is incorrect for the same reason as choice (B); it refers to a cc between 3-3 and 11, which is outside the interval [1,5][1, 5].

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