l=m125+50nThe equation gives the quantity l in terms of the quantities m and n. Which of the following equations correctly expresses n in terms of l and m ?Choose 1 answer:(A) n=50ml−125(B) n=50l−m125(C) n=50l−2m5(D) n=2m5−50l
Q. l=m125+50nThe equation gives the quantity l in terms of the quantities m and n. Which of the following equations correctly expresses n in terms of l and m ?Choose 1 answer:(A) n=50ml−125(B) n=50l−m125(C) n=50l−2m5(D) n=2m5−50l
Given equation: We start with the given equation:l=m125+50nOur goal is to solve for n in terms of l and m.
Isolating the term containing n: First, we isolate the term containing n on one side of the equation by subtracting m125 from both sides:l−m125=50n
Dividing both sides by 50: Next, we divide both sides of the equation by 50 to solve for n:n=50(l−m125)
Simplifying the right side: Now, we simplify the right side of the equation by distributing the division by 50 to both terms in the numerator:n=(50l)−(50m125)
Further simplification: We simplify the second term by dividing 125 by 50: n=(50l)−(50m125)
Expressing 2.5 as a fraction: We further simplify the second term by reducing the fraction50125, which simplifies to 2.5: n=(50l)−(m2.5)
Expressing 2.5 as a fraction: We further simplify the second term by reducing the fraction 50125, which simplifies to 2.5:n=(50l)−(m2.5)Finally, we express 2.5 as a fraction in terms of 2 to match the answer choices:2.5 is the same as 25, so we rewrite the equation as:n=(50l)−(2m5)
More problems from Compare linear and exponential growth