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Khan Academy
Quadr
Solve for 
x. Enter the solution

{:[2x^(2)-24 x+54=0],[" lesser "x=◻],[" greater "x=◻]:}

Khan Academy\newlineQuadr\newlineSolve for x x . Enter the solution\newline2x224x+54=0 lesser x= greater x= \begin{array}{l} 2 x^{2}-24 x+54=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}

Full solution

Q. Khan Academy\newlineQuadr\newlineSolve for x x . Enter the solution\newline2x224x+54=0 lesser x= greater x= \begin{array}{l} 2 x^{2}-24 x+54=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
  1. Write Quadratic Equation: Write down the quadratic equation. 2x224x+54=02x^2 - 24x + 54 = 0
  2. Divide and Simplify: Step 22: Divide the whole equation by 22 to simplify. x212x+27=0x^2 - 12x + 27 = 0
  3. Factor the Equation: Step 33: Factor the quadratic equation. (x3)(x9)=0(x - 3)(x - 9) = 0
  4. Solve for x: Step 44: Set each factor equal to 00 and solve for x. x3=0x - 3 = 0 or x9=0x - 9 = 0 x=3x = 3 or x=9x = 9
  5. Check Solutions: Step 55: Check the solutions by plugging them back into the original equation. For x=3x = 3: 2(3)224(3)+54=02(3)^2 - 24(3) + 54 = 0 1872+54=018 - 72 + 54 = 0 0=00 = 0 (True) For x=9x = 9: 2(9)224(9)+54=02(9)^2 - 24(9) + 54 = 0 162216+54=0162 - 216 + 54 = 0 0=00 = 0 (True)

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