Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Jacque needs to buy some pizzas for a party at her office. She's ordering from a restaurant that charges a $7.50\$7.50 delivery fee and $14\$14 per pizza. She wants to buy as many pizzas as she can, and she also needs to keep the delivery fee plus the cost of the pizzas under $60\$60. Each pizza is cut into 88 slices, and she wonders how many total slices she can afford. Let pp represent the number of pizzas that Jacque buys.

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Grade 7right chevron icon
Evaluate two-variable equations: word problemsright chevron icon

Full solution

Just a sec, we’re working out the solution to your problem...

Bytelearn - Loading gif

More problems from Evaluate two-variable equations: word problems

Question
The function b(t) b(t) gives the temperature (in degrees Celsius) of a pan of brownies by time t t (in minutes).\newlineWhat does ∫06b′(t)dt=93 \int_{0}^{6} b^{\prime}(t) d t=93 mean?\newlineChoose 11 answer:\newline(A) At t=6 t=6 minutes, the temperature of the brownies is 9393 degrees Celsius.\newlineB) At t=6 t=6 minutes, the brownies have an instantaneous rate of temperature change of 9393 degrees Celsius per minute.\newline(C) During the first six minutes, the temperature of the brownies increases an average of 9393 degrees Celsius per minute.\newline(D) The temperature of the brownies increased by 9393 degrees Celsius in the first six minutes.
Get tutor helpright-arrow

Posted 9 months ago

Question
The number of subscribers to a magazine is changing at a rate of r(t) r(t) subscribers per month (where t t is time in months).\newlineWhat does ∫810r′(t)dt=7 \int_{8}^{10} r^{\prime}(t) d t=7 mean?\newlineChoose 11 answer:\newline(A) As of month 1010 , the magazine had 77 subscribers.\newline(B) The average rate of change in subscribers between month 88 and month 1010 was 77 subscribers per month.\newline(C) The number of subscribers increased by 77 between t=8 t=8 and t=10 t=10 months.\newline(D) The rate of change of number of subscribers increased by 77 subscribers per month between t=8 t=8 and t=10 t=10 months.
Get tutor helpright-arrow

Posted 9 months ago

Question
A grocery store receives a shipment of bananas. The percent of the shipment that is still suitable for sale is decreasing at a rate of r(t) r(t) percent of the original shipment per day (where t t is the time in days). At t=2 t=2 , the grocery store found 85% 85 \% of the shipment to be suitable for sale.\newlineWhat does 0.85+∫24r(t)dt=0.6 mean?  0.85+\int_{2}^{4} r(t) d t=0.6 \text { mean? } \newlineChoose 11 answer:\newline(A) As of the fourth day, 60% 60 \% of the bananas suitable on the second day are still suitable.\newline(B) Between the second and fourth days, 60% 60 \% of the remaining bananas became unsuitable for sale per day.\newline(C) Between the second and fourth day, another 60% 60 \% of the bananas became unsuitable for sale.\newline(D) As of the fourth day, 60% 60 \% of the shipment was still suitable for sale.
Get tutor helpright-arrow

Posted 9 months ago

Question
The number of people exposed to a certain illness is increasing at a rate of r(t) r(t) people per day (where t t is the time in days). At t=12 t=12 , there were 115115 people exposed to the illness.\newlineWhat does 115+∫1220r(t)dt 115+\int_{12}^{20} r(t) d t represent?\newlineChoose 11 answer:\newline(A) The change in the number of people exposed to the illness between days 1212 and 2020\newline(B) The change in the rate at which people are exposed to the illness between days 1212 and 2020\newline(C) The time it takes for 2020 more people to be exposed to the illness\newline(D) The number of people exposed to the illness at t=20 t=20
Get tutor helpright-arrow

Posted 9 months ago

Question
The population of a town grows at a rate of r(t) r(t) people per year (where t t is time in years). At t=3 t=3 , the town's population was 10001000 people.\newlineWhat does 1000+∫38r(t)dt=1500 1000+\int_{3}^{8} r(t) d t=1500 mean?\newlineChoose 11 answer:\newline(A) The town's population grew by 15001500 people between t=3 t=3 and t=8 t=8 .\newline(B) The town's population grew at a rate of 15001500 people per year at t=8 t=8 .\newline(C) The average rate at which the population grew between t=3 t=3 and t=8 t=8 is 15001500 people per year.\newline(D) At t=8 t=8 , the town's population was 15001500 people.
Get tutor helpright-arrow

Posted 9 months ago

Question
The value of a computer is decreasing at a rate that is proportional at any time to the value of the computer at that time.\newlineThe computer is worth $850 \$ 850 initially, and it is worth $306 \$ 306 after 22 years.\newlineHow much will the computer be worth after 55 years?\newlineChoose 11 answer:\newline(A) $0 \$ 0 \newline(B) $66 \$ 66 \newline(C) $79 \$ 79
Get tutor helpright-arrow

Posted 9 months ago

Question
The expression 11(1.022)t 11(1.022)^{t} models the per capita gross domestic product (GDP) of the US, in thousands of dollars, as a function of the number of years since 19501950 .\newlineWhat does 11.022022 represent in this expression?\newlineChoose 11 answer:\newline(A) The per capita GDP in the US was $1022 \$ 1022 in 19501950.\newline(B) The maximum per capita GDP occurred 11.022022 years after 19501950 .\newline(C) The per capita GDP in the US is multiplied by approximately 11.022022 each year.
Get tutor helpright-arrow

Posted 9 months ago

Question
Carbon dating involves the measurement of the amount of carbon−14-14 in a sample. Archaeologists sometimes use carbon dating to estimate the number of years since an organism died. The function shows the ratio, R(t) R(t) , of carbon−14-14 remaining in a sample to the original amount of carbon−14-14 after t t years.\newlineR(t)=2−0.00175t R(t)=2^{-0.00175 t} \newlineIf one sample was 33 times as old as another sample of the same material, how would the carbon−14-14 ratios of the samples relate?\newlineChoose 11 answer:\newline(A) The ratio of the older sample would be 33 times the ratio of the newer sample.\newline(B) The ratio of the newer sample would be 33 times the ratio of the older sample.\newline(C) The ratio of the older sample would be the cube of the ratio of the newer sample.\newline(D) The ratio of the newer sample would be the cube of the ratio of the older sample.
Get tutor helpright-arrow

Posted 9 months ago

Question
D=1,874−0.55tD=1,874-0.55 t\newlineThe distance, DD, in meters, between an antarctic glacier and the coast tt days after January 11, 20102010 is approximated by the equation. How does the distance between the glacier and the coast change over time?\newlineChoose 11 answer:\newline(A) The glacier moves 0.550.55 meters per day closer to the shore.\newline(B) The glacier moves 1,8741,874 meters per day closer to the shore.\newline(C) The glacier moves 0.550.55 meters per day further from the shore.\newline(D) The glacier moves 1,8741,874 meters per day further from the shore.
Get tutor helpright-arrow

Posted 8 months ago

Question
Derin's boyfriend in Japan is $0.19\$0.19 per minute. The rate to call her family in Turkey is $0.12\$0.12 per minute. Derin wants to spend at least 3030 minutes calling her family in Turkey. Which of the following systems of inequalities best represents the relationship between JJ, the number of minutes Derin calls Japan, and TT, the number of minutes Derin calls Turkey? \newlineChoose 11 answer:\newline(A) 0.19J+0.12T≤250.19J+0.12T \leq 25\newlineT≤30T \leq 30\newline(B) 0.19J+0.12T≥250.19J+0.12T \geq 25\newlineT≤30T \leq 30\newline(C) 0.19J+0.12T≤250.19J+0.12T \leq 25\newlineT≥30T \geq 30\newline(D) 0.19J+0.12T≥250.19J+0.12T \geq 25\newlineT≥30T \geq 30
Get tutor helpright-arrow

Posted 8 months ago

View all (54)

Related topics

Algebra - Order of OperationsAlgebra - Distributive Property`X` and `Y` AxesGeometry - Scalene TriangleCommon MultipleGeometry - Quadrant