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How does g(x)=9xg(x) = 9^x change over the interval from x=5x = 5 to x=6x = 6?\newlineChoices:\newline(A)g(x)g(x) increases by 900%900\%\newline(B)g(x)g(x) decreases by 99\newline(C)g(x)g(x) decreases by 9%9\%\newline(D)g(x)g(x) increases by a factor of 99

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Q. How does g(x)=9xg(x) = 9^x change over the interval from x=5x = 5 to x=6x = 6?\newlineChoices:\newline(A)g(x)g(x) increases by 900%900\%\newline(B)g(x)g(x) decreases by 99\newline(C)g(x)g(x) decreases by 9%9\%\newline(D)g(x)g(x) increases by a factor of 99
  1. Calculate g(5)g(5): Calculate g(5)g(5) by substituting x=5x = 5 into g(x)=9xg(x) = 9^x.\newlineg(5)=95g(5) = 9^5
  2. Calculate g(6)g(6): Calculate g(6)g(6) by substituting x=6x = 6 into g(x)=9xg(x) = 9^x.\newlineg(6)=96g(6) = 9^6
  3. Compare g(5)g(5) and g(6)g(6): Compare g(5)g(5) and g(6)g(6) to determine the change.\newlineSince 969^6 is 99 times 959^5, g(x)g(x) increases by a factor of 99 from x=5x = 5 to g(6)g(6)00.

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