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How does g(x)=8xg(x)= 8^x change over the interval from x=3x = 3 to x=4x = 4?\newlineChoices:\newline(A) g(x)g(x) increases by 800%800\%\newline(B) g(x)g(x) decreases by 88\newline(C) g(x)g(x) increases by 8%8\%\newline(D) g(x)g(x) increases by a factor of 88

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Q. How does g(x)=8xg(x)= 8^x change over the interval from x=3x = 3 to x=4x = 4?\newlineChoices:\newline(A) g(x)g(x) increases by 800%800\%\newline(B) g(x)g(x) decreases by 88\newline(C) g(x)g(x) increases by 8%8\%\newline(D) g(x)g(x) increases by a factor of 88
  1. Calculate g(33): Calculate g(3) g(3) .\newlineg(3)=83 g(3) = 8^3 \newlineg(3)=512 g(3) = 512
  2. Calculate g(44): Calculate g(4) g(4) .\newlineg(4)=84 g(4) = 8^4 \newlineg(4)=4096 g(4) = 4096
  3. Find the ratio: Find the ratio g(4)g(3) \frac{g(4)}{g(3)} .\newlineg(4)g(3)=4096512 \frac{g(4)}{g(3)} = \frac{4096}{512} \newlineg(4)g(3)=8 \frac{g(4)}{g(3)} = 8
  4. Determine the change: \newlineSince the ratio is 88, g(x) g(x) increases by a factor of 88.

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