Heron's Formula: Unit test The area of the triangle with sides 11cm,9cm and 12cm is of the form ysqrt35cm^(2). Find the value of y. ◻

Calculate semi-perimeter: Step 1: Calculate the semi-perimeter (s) of the triangle. s = (a + b + c) / 2 s = (11 + 9 + 12) / 2 s = 32 / 2 s = 16 cmApply Heron's Formula: Step 2: Apply Heron's Formula to find the area (A). A = √(s(s - a)(s - b)(s - c)) A = √(16(16 - 11)(16 - 9)(16 - 12)) A = √(16 * 5 * 7 * 4) A = √(2240) A = √(35 * 64) A = 8√35 cm²Compare and find y: Step 3: Compare the expression 8√35 cm² with y√35 cm² to find y. From A = y√35 cm², we have 8√35 cm² = y√35 cm² Thus, y = 8

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Heron's Formula: Unit test
The area of the triangle with sides
11cm,9cm and
12cm is of the form
ysqrt35cm^(2).
Find the value of
y.

◻

Heron's Formula: Unit test $\newline$ The area of the triangle with sides $11 \mathrm{~cm}, 9 \mathrm{~cm}$ and $12 \mathrm{~cm}$ is of the form $y \sqrt{35} \mathrm{~cm}^{2}$ . $\newline$ Find the value of $y$ . $\newline$ $\square$

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Q. Heron's Formula: Unit test

\newline

The area of the triangle with sides

11 \mathrm{~cm}, 9 \mathrm{~cm}

and

12 \mathrm{~cm}

is of the form

y \sqrt{35} \mathrm{~cm}^{2}

\newline

Find the value of

y

\newline

\square

Calculate semi-perimeter: Step $1$ : Calculate the semi-perimeter $s$ of the triangle. $\newline$ $s = \frac{a + b + c}{2}$ $\newline$ $s = \frac{11 + 9 + 12}{2}$ $\newline$ $s = \frac{32}{2}$ $\newline$ $s = 16 \, \text{cm}$
Apply Heron's Formula: Step $2$ : Apply Heron's Formula to find the area $A$ . $A = \sqrt{s(s - a)(s - b)(s - c)}$ $A = \sqrt{16(16 - 11)(16 - 9)(16 - 12)}$ $A = \sqrt{16 \times 5 \times 7 \times 4}$ $A = \sqrt{2240}$ $A = \sqrt{35 \times 64}$ $A = 8\sqrt{35} \text{ cm}^2$
Compare and find $y$ : Step $3$ : Compare the expression $8\sqrt{35}$ cm $^2$ with $y\sqrt{35}$ cm $^2$ to find $y$ . From $A = y\sqrt{35}$ cm $^2$ , we have $8\sqrt{35}$ cm $^2$ = $y\sqrt{35}$ cm $^2$ Thus, $8\sqrt{35}$ $2$