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Google Classroom Microsoft Teams {:[p(n)=(n^(3)-12n^(2)+47 n-60)(n-4)],[q(n)=(n+13)(n-4)]:} The functions p and q are defined. One of the functions has a zero at n=5. What is the value of p(5)+q(5) ? ◻

Google Classroom\newlineMicrosoft Teams\newlinep(n)=(n3−12n2+47n−60)(n−4)q(n)=(n+13)(n−4) \begin{array}{l} p(n)=\left(n^{3}-12 n^{2}+47 n-60\right)(n-4) \\ q(n)=(n+13)(n-4) \end{array} \newlineThe functions p p and q q are defined. One of the functions has a zero at n=5 n=5 . What is the value of p(5)+q(5) p(5)+q(5) ?\newline□ \square

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Q. Google Classroom\newlineMicrosoft Teams\newlinep(n)=(n3−12n2+47n−60)(n−4)q(n)=(n+13)(n−4) \begin{array}{l} p(n)=\left(n^{3}-12 n^{2}+47 n-60\right)(n-4) \\ q(n)=(n+13)(n-4) \end{array} \newlineThe functions p p and q q are defined. One of the functions has a zero at n=5 n=5 . What is the value of p(5)+q(5) p(5)+q(5) ?\newline□ \square
  1. Evaluate p(5)p(5): Evaluate p(5)p(5). p(n)=(n3−12n2+47n−60)(n−4)p(n) = (n^3 - 12n^2 + 47n - 60)(n - 4) p(5)=(53−12imes52+47imes5−60)(5−4)p(5) = (5^3 - 12 imes 5^2 + 47 imes 5 - 60)(5 - 4) p(5)=(125−300+235−60)(1)p(5) = (125 - 300 + 235 - 60)(1) p(5)=0p(5) = 0
  2. Evaluate q(5)q(5): Step 22: Evaluate q(5)q(5). q(n)=(n+13)(n−4)q(n) = (n + 13)(n - 4) q(5)=(5+13)(5−4)q(5) = (5 + 13)(5 - 4) q(5)=18imes1q(5) = 18 imes 1 q(5)=18q(5) = 18
  3. Add p(5)p(5) and q(5)q(5): Step 33: Add p(5)p(5) and q(5)q(5). p(5)+q(5)=0+18p(5) + q(5) = 0 + 18 p(5)+q(5)=18p(5) + q(5) = 18

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