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Given 
P(A)=0.74,P(B)=0.6 and 
P(A∣B)=0.9, find the value of 
P(A and 
B), rounding to the nearest thousandth, if necessary.
Answer:

Given P(A)=0.74,P(B)=0.6 P(A)=0.74, P(B)=0.6 and P(AB)=0.9 P(A \mid B)=0.9 , find the value of P(A P(A and B) B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:

Full solution

Q. Given P(A)=0.74,P(B)=0.6 P(A)=0.74, P(B)=0.6 and P(AB)=0.9 P(A \mid B)=0.9 , find the value of P(A P(A and B) B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:
  1. Define conditional probability: Understand the definition of conditional probability. The conditional probability P(AB)P(A|B) is defined as the probability of event AA occurring given that event BB has occurred. The formula for conditional probability is P(AB)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}. We can rearrange this formula to solve for P(A and B)P(A \text{ and } B) by multiplying both sides by P(B)P(B).
  2. Calculate P(A and B)P(A \text{ and } B): Calculate the value of P(A and B)P(A \text{ and } B). Using the formula from Step 11, we have P(AB)×P(B)=P(A and B)P(A|B) \times P(B) = P(A \text{ and } B). We know that P(AB)=0.9P(A|B) = 0.9 and P(B)=0.6P(B) = 0.6. So, P(A and B)=0.9×0.6P(A \text{ and } B) = 0.9 \times 0.6.
  3. Perform multiplication: Perform the multiplication to find P(A and B)P(A \text{ and } B).\newlineP(A and B)=0.9×0.6=0.54P(A \text{ and } B) = 0.9 \times 0.6 = 0.54.
  4. Round answer: Round the answer to the nearest thousandth if necessary.\newlineSince the answer is already at the thousandth place, no rounding is necessary.

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