Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Fully simplify the expression below and write your answer as a single fraction.

(2x^(4)-8x^(2))/(x^(4)-10x^(3))*(x+7)/(4x^(2)+36 x+56)
Answer:

Fully simplify the expression below and write your answer as a single fraction.\newline2x48x2x410x3x+74x2+36x+56 \frac{2 x^{4}-8 x^{2}}{x^{4}-10 x^{3}} \cdot \frac{x+7}{4 x^{2}+36 x+56} \newlineAnswer:

Full solution

Q. Fully simplify the expression below and write your answer as a single fraction.\newline2x48x2x410x3x+74x2+36x+56 \frac{2 x^{4}-8 x^{2}}{x^{4}-10 x^{3}} \cdot \frac{x+7}{4 x^{2}+36 x+56} \newlineAnswer:
  1. Factor Numerator and Denominator: First, factor the numerator and the denominator of the first fraction.\newlineThe numerator 2x48x22x^4 - 8x^2 can be factored by taking out the common factor of 2x22x^2, resulting in 2x2(x24)2x^2(x^2 - 4).\newlineThe denominator x410x3x^4 - 10x^3 can be factored by taking out the common factor of x3x^3, resulting in x3(x10)x^3(x - 10).
  2. Factor Second Fraction: Now, factor the numerator and the denominator of the second fraction. The numerator x+7x + 7 is already in its simplest form. The denominator 4x2+36x+564x^2 + 36x + 56 can be factored by grouping. We can factor out a 44, resulting in 4(x2+9x+14)4(x^2 + 9x + 14). Then, we can factor the quadratic as 4(x+2)(x+7)4(x + 2)(x + 7).
  3. Combine and Cancel Common Factors: Combine the factored forms of the numerator and denominator to rewrite the original expression.\newlineThe expression becomes (2x2(x24))/(x3(x10))×(x+7)/(4(x+2)(x+7))(2x^2(x^2 - 4))/(x^3(x - 10)) \times (x + 7)/(4(x + 2)(x + 7)).
  4. Simplify Expression: Next, we can cancel out common factors from the numerator and the denominator across the fractions.\newlineThe (x+7)(x + 7) terms cancel each other out. We are left with 2x2(x24)x3(x10)×14(x+2)\frac{2x^2(x^2 - 4)}{x^3(x - 10)} \times \frac{1}{4(x + 2)}.
  5. Recognize Difference of Squares: Now, we can simplify the expression further by canceling out any common factors. The x2x^2 term in the numerator can cancel out two xx's from the x3x^3 term in the denominator. We are left with 2(x24)x(x10)×14(x+2)\frac{2(x^2 - 4)}{x(x - 10)} \times \frac{1}{4(x + 2)}.
  6. Substitute Factored Form: We can now simplify the expression (x24)(x^2 - 4) by recognizing it as a difference of squares.\newlineThe expression x24x^2 - 4 can be factored into (x+2)(x2)(x + 2)(x - 2).
  7. Cancel Common Terms: Substitute the factored form of x24x^2 - 4 into the expression.\newlineWe now have (2(x+2)(x2))/(x(x10))×1/(4(x+2))(2(x + 2)(x - 2))/(x(x - 10)) \times 1/(4(x + 2)).
  8. Combine Remaining Factors: Cancel out the common (x+2)(x + 2) terms from the numerator and the denominator.\newlineWe are left with 2(x2)x(x10)×14\frac{2(x - 2)}{x(x - 10)} \times \frac{1}{4}.
  9. Final Simplified Expression: Combine the remaining factors to form a single fraction.\newlineThe expression simplifies to (2(x2))/(4x(x10))(2(x - 2))/(4x(x - 10)).
  10. Final Simplified Expression: Combine the remaining factors to form a single fraction. The expression simplifies to (2(x2))/(4x(x10))(2(x - 2))/(4x(x - 10)).Finally, we can simplify the fraction by dividing both the numerator and the denominator by 22. The final simplified expression is (x2)/(2x(x10))(x - 2)/(2x(x - 10)).

More problems from Operations with rational exponents