Fully simplify the expression below and write your answer as a single fraction. (x+6)/(x^(2)+9x+18)*(x^(3)-x^(2)-12 x)/(x^(3)-11x^(2)+28 x) Answer:

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Fully simplify the expression below and write your answer as a single fraction.  (x+6)/(x^(2)+9x+18)*(x^(3)-x^(2)-12 x)/(x^(3)-11x^(2)+28 x) Answer:

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Factor Polynomials: First, factor the polynomials in the numerators and denominators where possible. The denominator x^2 + 9x + 18 can be factored into (x + 3)(x + 6). The numerator x^3 - x^2 - 12x can be factored by taking out a common factor of x, resulting in x(x^2 - x - 12). Further factoring the quadratic gives x(x - 4)(x + 3). The denominator x^3 - 11x^2 + 28x can be factored by taking out a common factor of x, resulting in x(x^2 - 11x + 28). Further factoring the quadratic gives x(x - 4)(x - 7).Rewrite with Factored Forms: Now, we rewrite the original expression with the factored forms: ((x + 6) / ((x + 3)(x + 6))) * (x(x - 4)(x + 3) / (x(x - 4)(x - 7))).Cancel Common Factors: Next, we cancel out the common factors in the numerator and the denominator. The (x + 6) terms cancel each other out, as do the (x + 3) terms and the x terms. The (x - 4) terms also cancel each other out. This leaves us with 1 / (x - 7).Final Simplification: The expression is now fully simplified, and no further simplification is possible. The final answer is 1 / (x - 7).

Fully simplify the expression below and write your answer as a single fraction. $\newline$ $\frac{x+6}{x^{2}+9 x+18} \cdot \frac{x^{3}-x^{2}-12 x}{x^{3}-11 x^{2}+28 x}$ $\newline$ Answer:

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Fully simplify the expression below and write your answer as a single fraction.\newlinex+6x2+9x+18⋅x3−x2−12xx3−11x2+28x \frac{x+6}{x^{2}+9 x+18} \cdot \frac{x^{3}-x^{2}-12 x}{x^{3}-11 x^{2}+28 x} x2+9x+18x+6​⋅x3−11x2+28xx3−x2−12x​\newlineAnswer:

Fully simplify the expression below and write your answer as a single fraction. $\newline$ $\frac{x+6}{x^{2}+9 x+18} \cdot \frac{x^{3}-x^{2}-12 x}{x^{3}-11 x^{2}+28 x}$ $\newline$ Answer: