Fully simplify the expression below and write your answer as a single fraction. (2x^(2)-14 x)/(x^(5)-6x^(4)-7x^(3))*(x^(2)-9x-10)/(x^(2)-16 x+60) Answer:

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Fully simplify the expression below and write your answer as a single fraction.  (2x^(2)-14 x)/(x^(5)-6x^(4)-7x^(3))*(x^(2)-9x-10)/(x^(2)-16 x+60) Answer:

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Identify Given Expression: Identify the given expression and look for common factors in the numerator and denominator that can be simplified. The expression is: (2x^2 - 14x) / (x^5 - 6x^4 - 7x^3) * (x^2 - 9x - 10) / (x^2 - 16x + 60)Factor Numerator and Denominator: Factor the first numerator and the first denominator. 2x^2 - 14x can be factored as 2x(x - 7). x^5 - 6x^4 - 7x^3 can be factored as x^3(x^2 - 6x - 7).Factor Second Numerator and Denominator: Factor the second numerator and the second denominator. x^2 - 9x - 10 can be factored as (x - 10)(x + 1). x^2 - 16x + 60 can be factored as (x - 10)(x - 6).Rewrite with Factored Terms: Rewrite the expression with the factored terms. (2x(x - 7)) / (x^3(x^2 - 6x - 7)) * ((x - 10)(x + 1)) / ((x - 10)(x - 6))Cancel Common Factors: Cancel out the common factors in the numerator and denominator. The (x - 10) terms cancel out, and one x term from the first denominator cancels with the x term in the first numerator. The simplified expression is now: (2(x - 7)) / (x^2(x^2 - 6x - 7)) * (x + 1) / (x - 6)Factor Remaining Quadratic: Factor the remaining quadratic in the denominator. x^2 - 6x - 7 can be factored as (x - 7)(x + 1).Rewrite with Newly Factored Term: Rewrite the expression with the newly factored term. (2(x - 7)) / (x^2(x - 7)(x + 1)) * (x + 1) / (x - 6)Cancel Common Factors: Cancel out the common factors in the numerator and denominator. The (x - 7) and (x + 1) terms cancel out. The simplified expression is now: 2 / (x^2(x - 6))Write Final Simplified Expression: Write the final simplified expression as a single fraction. The final answer is: 2 / (x^3 - 6x^2)

Fully simplify the expression below and write your answer as a single fraction. $\newline$ $\frac{2 x^{2}-14 x}{x^{5}-6 x^{4}-7 x^{3}} \cdot \frac{x^{2}-9 x-10}{x^{2}-16 x+60}$ $\newline$ Answer:

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Fully simplify the expression below and write your answer as a single fraction.\newline2x2−14xx5−6x4−7x3⋅x2−9x−10x2−16x+60 \frac{2 x^{2}-14 x}{x^{5}-6 x^{4}-7 x^{3}} \cdot \frac{x^{2}-9 x-10}{x^{2}-16 x+60} x5−6x4−7x32x2−14x​⋅x2−16x+60x2−9x−10​\newlineAnswer:

Fully simplify the expression below and write your answer as a single fraction. $\newline$ $\frac{2 x^{2}-14 x}{x^{5}-6 x^{4}-7 x^{3}} \cdot \frac{x^{2}-9 x-10}{x^{2}-16 x+60}$ $\newline$ Answer: