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Find the yy-intercept of the parabola y=x2+1y = x^2 + 1. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____

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Q. Find the yy-intercept of the parabola y=x2+1y = x^2 + 1. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____
  1. Find y-intercept: To find the y-intercept of the parabola, we need to determine the value of yy when x=0x = 0.
  2. Substitute x=0x=0: Substitute x=0x = 0 into the equation y=x2+1y = x^2 + 1.\newliney=(0)2+1y = (0)^2 + 1\newliney=0+1y = 0 + 1\newliney=1y = 1
  3. Identify y-intercept point: The y-intercept of the parabola is the point where the graph crosses the y-axis, which occurs at (0,y)(0, y). Since we found y=1y = 1 when x=0x = 0, the y-intercept is at (0,1)(0, 1).

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