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Find the yy-intercept of the parabola y=x2+12y = x^2 + \frac{1}{2}. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____

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Q. Find the yy-intercept of the parabola y=x2+12y = x^2 + \frac{1}{2}. \newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____
  1. Determine y-intercept: To find the y-intercept of the parabola, we need to determine the value of yy when x=0x = 0.
  2. Substitute x=0x=0: Substitute x=0x = 0 into the equation y=x2+12y = x^2 + \frac{1}{2}.\newliney=(0)2+12y = (0)^2 + \frac{1}{2}\newliney=0+12y = 0 + \frac{1}{2}\newliney=12y = \frac{1}{2}
  3. Identify y-intercept point: The y-intercept of the parabola is the point where the graph of the parabola crosses the y-axis. Since we have found the value of yy when x=0x = 0, this value represents the y-intercept.

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