Q. Find the positive solution of the equation.4x27+15=527Answer:
Subtract 15: Subtract 15 from both sides of the equation to isolate the term with the variable x.4x(7/2)+15−15=527−154x(7/2)=512
Divide by 4: Divide both sides of the equation by 4 to solve for x27.44x27=4512\(x^{\frac{7}{2}} = 128\)]
Recognize power of \(2\): Recognize that \(128\) is a power of \(2\). Specifically, \(128 = 2^7\).\(\newline\)\(x^{\frac{7}{2}} = 2^7\)
Raise to power: To solve for \(x\), we need to get rid of the exponent \((7/2)\). We can do this by raising both sides of the equation to the power of \((2/7)\).\[(x^{(7/2)})^{(2/7)} = (2^7)^{(2/7)}x=27∗(2/7)x=22
Calculate x: Calculate 22 to find the value of x. x=22 x=4
More problems from Operations with rational exponents