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Find the distance between the points (6,4)(6,4) and (2,7)(2,7).\newlineWrite your answer as a whole number or a fully simplified radical expression. Do not round.\newline__\_\_ units

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Q. Find the distance between the points (6,4)(6,4) and (2,7)(2,7).\newlineWrite your answer as a whole number or a fully simplified radical expression. Do not round.\newline__\_\_ units
  1. Identify Coordinates: To find the distance between the points (6,4)(6,4) and (2,7)(2,7), we will use the distance formula, which is (x2x1)2+(y2y1)2\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. Here, (x1,y1)=(6,4)(x_1, y_1) = (6, 4) and (x2,y2)=(2,7)(x_2, y_2) = (2, 7).
  2. Calculate X-coordinate Difference: First, we calculate the difference in the x-coordinates: (x2x1)=(26)=4(x_2 - x_1) = (2 - 6) = -4. Squaring this difference gives us (4)2=16(-4)^2 = 16.
  3. Calculate Y-coordinate Difference: Next, we calculate the difference in the y-coordinates: (y2y1)=(74)=3(y_2 - y_1) = (7 - 4) = 3. Squaring this difference gives us (3)2=9(3)^2 = 9.
  4. Add Squares of Differences: Now, we add the squares of the differences in the xx and yy coordinates: 16+9=2516 + 9 = 25.
  5. Find Distance: Finally, we take the square root of the sum to find the distance: 25=5\sqrt{25} = 5. Therefore, the distance between the points (6,4)(6,4) and (2,7)(2,7) is 55 units.

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