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Find the sum of the first 9 terms in the following geometric series.
Do not round your answer.

64+32+16+dots

Find the sum of the first 99 terms in the following geometric series.\newlineDo not round your answer.\newline64+32+16+ 64+32+16+\ldots

Full solution

Q. Find the sum of the first 99 terms in the following geometric series.\newlineDo not round your answer.\newline64+32+16+ 64+32+16+\ldots
  1. Identify Terms and Ratio: Identify the first term aa and the common ratio rr of the geometric series.\newlineThe first term a=64a = 64.\newlineTo find the common ratio rr, divide the second term by the first term: r=3264=0.5r = \frac{32}{64} = 0.5.
  2. Use Sum Formula: Use the formula for the sum of the first nn terms of a geometric series: Sn=a(1rn)(1r)S_n = \frac{a(1 - r^n)}{(1 - r)}, where SnS_n is the sum of the first nn terms, aa is the first term, rr is the common ratio, and nn is the number of terms.\newlineHere, n=9n = 9, a=64a = 64, and r=0.5r = 0.5.
  3. Calculate Substitution: Substitute the values into the formula and calculate the sum.\newlineS9=64(10.59)/(10.5)S_9 = 64(1 - 0.5^9) / (1 - 0.5)\newlineCalculate 0.590.5^9.
  4. Calculate 0.590.5^9: 0.59=0.5×0.5×0.5×0.5×0.5×0.5×0.5×0.5×0.50.5^9 = 0.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5\newline0.59=0.0019531250.5^9 = 0.001953125
  5. Perform Subtraction and Division: Substitute 0.590.5^9 into the formula and calculate the sum.\newlineS9=64(10.001953125)/(10.5)S_9 = 64(1 - 0.001953125) / (1 - 0.5)\newlineS9=64(0.998046875)/0.5S_9 = 64(0.998046875) / 0.5
  6. Perform Subtraction and Division: Substitute 0.590.5^9 into the formula and calculate the sum.\newlineS9=64(10.001953125)/(10.5)S_9 = 64(1 - 0.001953125) / (1 - 0.5)\newlineS9=64(0.998046875)/0.5S_9 = 64(0.998046875) / 0.5 Perform the subtraction and division to find the sum.\newlineS9=64×0.998046875/0.5S_9 = 64 \times 0.998046875 / 0.5\newlineS9=63.875/0.5S_9 = 63.875 / 0.5\newlineS9=127.75S_9 = 127.75

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