Find the distance between the points (10,7) and (10,2). ____ units

Apply distance formula: Step 1: Apply the distance formula sqrt((x_2-x_1)^2 + (y_2-y_1)^2). Given points (x_1, y_1) = (10, 7) and (x_2, y_2) = (10, 2). Calculate (x_2-x_1)^2 and (y_2-y_1)^2. x_2 - x_1 = 10 - 10 = 0, so (x_2-x_1)^2 = 0^2 = 0. y_2 - y_1 = 2 - 7 = -5, so (y_2-y_1)^2 = (-5)^2 = 25.Calculate sum of squares: Step 2: Calculate the square root of the sum of squares. sqrt((x_2-x_1)^2 + (y_2-y_1)^2) = sqrt(0 + 25) = sqrt(25) = 5.

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Find the distance between the points $(10,7)$ and $(10,2)$ . $\newline$ $\_\_\_\_$ units

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Algebra 1

Distance between two points

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Q. Find the distance between the points

(10,7)

and

(10,2)

\newline

\_\_\_\_

units

Apply distance formula: Step $1$ : Apply the distance formula $\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ . $\newline$ Given points $(x_1, y_1) = (10, 7)$ and $(x_2, y_2) = (10, 2)$ . $\newline$ Calculate $(x_2-x_1)^2$ and $(y_2-y_1)^2$ . $\newline$ $x_2 - x_1 = 10 - 10 = 0$ , so $(x_2-x_1)^2 = 0^2 = 0$ . $\newline$ $y_2 - y_1 = 2 - 7 = -5$ , so $(y_2-y_1)^2 = (-5)^2 = 25$ .
Calculate sum of squares: Step $2$ : Calculate the square root of the sum of squares. $\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{0 + 25} = \sqrt{25} = 5$ .