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Let’s check out your problem:
Find four rational numbers between
\newline
2
7
to
8
21
\frac{2}{7} \text { to } \frac{8}{21}
7
2
to
21
8
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Math Problems
Precalculus
Operations with rational exponents
Full solution
Q.
Find four rational numbers between
\newline
2
7
to
8
21
\frac{2}{7} \text { to } \frac{8}{21}
7
2
to
21
8
Convert to common denominator:
Convert
(
8
21
)
(\frac{8}{21})
(
21
8
)
to a common denominator with
(
2
7
)
(\frac{2}{7})
(
7
2
)
.
8
21
=
8
21
×
1
=
8
21
\frac{8}{21} = \frac{8}{21} \times 1 = \frac{8}{21}
21
8
=
21
8
×
1
=
21
8
,
2
7
=
2
7
×
3
3
=
6
21
\frac{2}{7} = \frac{2}{7} \times \frac{3}{3} = \frac{6}{21}
7
2
=
7
2
×
3
3
=
21
6
,Now we have
(
6
21
)
(\frac{6}{21})
(
21
6
)
and
(
8
21
)
(\frac{8}{21})
(
21
8
)
.
Find the difference:
Find the difference between the two
fractions
.
\newline
Difference =
(
8
21
)
−
(
6
21
)
=
(
2
21
)
(\frac{8}{21}) - (\frac{6}{21}) = (\frac{2}{21})
(
21
8
)
−
(
21
6
)
=
(
21
2
)
.
Divide by
5
5
5
for step size:
Divide the difference by
5
5
5
to find the step size for four numbers.
\newline
Step size =
(
2
/
21
)
/
5
=
(
2
/
105
)
(2/21) / 5 = (2/105)
(
2/21
)
/5
=
(
2/105
)
.
Calculate first number:
Calculate the first rational number.
\newline
First number =
(
6
21
)
+
(
2
105
)
=
(
30
105
)
+
(
2
105
)
=
(
32
105
)
(\frac{6}{21}) + (\frac{2}{105}) = (\frac{30}{105}) + (\frac{2}{105}) = (\frac{32}{105})
(
21
6
)
+
(
105
2
)
=
(
105
30
)
+
(
105
2
)
=
(
105
32
)
.
Calculate second number:
Calculate the second rational number.
\newline
Second number =
(
32
105
)
+
(
2
105
)
=
(
34
105
)
(\frac{32}{105}) + (\frac{2}{105}) = (\frac{34}{105})
(
105
32
)
+
(
105
2
)
=
(
105
34
)
.
Calculate third number:
Calculate the third rational number.
\newline
Third number =
(
34
105
)
+
(
2
105
)
=
(
36
105
)
(\frac{34}{105}) + (\frac{2}{105}) = (\frac{36}{105})
(
105
34
)
+
(
105
2
)
=
(
105
36
)
.
Calculate fourth number:
Calculate the fourth rational number.
\newline
Fourth number =
(
36
105
)
+
(
2
105
)
=
(
38
105
)
(\frac{36}{105}) + (\frac{2}{105}) = (\frac{38}{105})
(
105
36
)
+
(
105
2
)
=
(
105
38
)
.
More problems from Operations with rational exponents
Question
f
(
x
)
=
6
x
+
5
2
−
14
+
5
x
f(x)=\frac{6 x+5}{2-\sqrt{14+5 x}}
f
(
x
)
=
2
−
14
+
5
x
6
x
+
5
\newline
We want to find
lim
x
→
−
2
f
(
x
)
\lim _{x \rightarrow-2} f(x)
lim
x
→
−
2
f
(
x
)
.
\newline
What happens when we use direct substitution?
\newline
Choose
1
1
1
answer:
\newline
(A) The limit exists, and we found it!
\newline
(B) The limit doesn't exist (probably an asymptote).
\newline
(C) The result is indeterminate.
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What is the value of
d
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d
x
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\frac{d^{2} y}{d x^{2}}
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(
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)
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\newline
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What is the area of the region bound by the graphs of
f
(
x
)
=
x
−
2
,
g
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x
)
=
14
−
x
f(x)=\sqrt{x-2}, g(x)=14-x
f
(
x
)
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−
2
,
g
(
x
)
=
14
−
x
, and
x
=
2
x=2
x
=
2
?
\newline
Choose
1
1
1
answer:
\newline
(A)
19
6
\frac{19}{6}
6
19
\newline
(B)
99
2
\frac{99}{2}
2
99
\newline
(C)
151
2
\frac{151}{2}
2
151
\newline
(D)
45
2
\frac{45}{2}
2
45
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Let
g
(
x
)
=
x
4
3
g(x)=x^{\frac{4}{3}}
g
(
x
)
=
x
3
4
.
\newline
g
′
(
27
)
=
g^{\prime}(27)=
g
′
(
27
)
=
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ln
(
1
e
)
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ln
(
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1
)
\newline
Answer:
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ln
(
1
e
)
\ln \left(\frac{1}{e}\right)
ln
(
e
1
)
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Answer:
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sin
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1
(
5
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2
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)
3
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y
=
(
sin
−
1
(
5
x
2
)
)
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10
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3
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5
x
2
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6
x
)
÷
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2
x
2
)
\left(10x^{3}-5x^{2}-6x\right)\div\left(2x^{2}\right)
(
10
x
3
−
5
x
2
−
6
x
)
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(
2
x
2
)
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Question
y
=
cos
4
x
sin
4
x
y=\cos^{4}x\sin^{4}x
y
=
cos
4
x
sin
4
x
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10
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3
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