Q. Factor the following expression completely.x4−6x3+5x2−16x2+96x−80Answer:
Combine Like Terms: First, we need to combine like terms in the expression x4−6x3+5x2−16x2+96x−80. Combining the x2 terms: 5x2−16x2=−11x2. The expression now becomes x4−6x3−11x2+96x−80.
Group and Factor: Next, we look for common factors in groups of terms. We can group the first three terms and the last two terms separately.Grouping: (x4−6x3−11x2)+(96x−80).
Factor Quadratic: Now, we factor by grouping. For the first group x4−6x3−11x2, we can factor out an x2. This gives us x2(x2−6x−11). For the second group 96x−80, we can factor out a 16. This gives us 16(6x−5). The expression now becomes x2(x2−6x−11)+16(6x−5).
Substitute Factored Form: We now look for common factors between the two groups. There are no common factors between x2−6x−11 and 6x−5, so we cannot factor further by grouping.We must now factor the quadratic x2−6x−11.
Check for Common Factors: To factor the quadratic x2−6x−11, we look for two numbers that multiply to −11 and add to −6. The numbers −11 and 1 satisfy these conditions. We can write x2−6x−11 as (x−11)(x+1).
Final Factored Form: Now we substitute the factored form of the quadratic back into the expression. The expression becomes x2(x−11)(x+1)+16(6x−5).
Final Factored Form: Now we substitute the factored form of the quadratic back into the expression. The expression becomes x2(x−11)(x+1)+16(6x−5).We have factored the expression as much as possible. The final factored form is x2(x−11)(x+1)+16(6x−5). However, we need to check if there is a common factor that we might have missed.
Final Factored Form: Now we substitute the factored form of the quadratic back into the expression. The expression becomes x2(x−11)(x+1)+16(6x−5).We have factored the expression as much as possible. The final factored form is x2(x−11)(x+1)+16(6x−5). However, we need to check if there is a common factor that we might have missed.Upon re-examining the expression x2(x−11)(x+1)+16(6x−5), we realize that there is no common factor between the two groups, and the quadratic has been factored correctly. Therefore, the expression is fully factored.
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