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Factor the following expression completely.

x^(4)+2x^(3)-3x^(2)-25x^(2)-50 x+75
Answer:

Factor the following expression completely.\newlinex4+2x33x225x250x+75 x^{4}+2 x^{3}-3 x^{2}-25 x^{2}-50 x+75 \newlineAnswer:

Full solution

Q. Factor the following expression completely.\newlinex4+2x33x225x250x+75 x^{4}+2 x^{3}-3 x^{2}-25 x^{2}-50 x+75 \newlineAnswer:
  1. Combine Like Terms: First, we need to combine like terms in the expression.\newlinex4+2x33x225x250x+75x^4 + 2x^3 - 3x^2 - 25x^2 - 50x + 75\newlineCombine the x2x^2 terms: 3x225x2=28x2-3x^2 - 25x^2 = -28x^2\newlineThe expression becomes:\newlinex4+2x328x250x+75x^4 + 2x^3 - 28x^2 - 50x + 75
  2. Factor by Grouping: Next, we look for common factors in groups of terms.\newlineGroup the terms as follows: (x4+2x3)+(28x250x)+75(x^4 + 2x^3) + (-28x^2 - 50x) + 75\newlineNow factor by grouping.\newlineFirst group: x3x^3 is a common factor in x4+2x3x^4 + 2x^3, so factor it out.\newlinex3(x+2)x^3(x + 2)\newlineSecond group: 2-2 is a common factor in 28x250x-28x^2 - 50x, so factor it out.\newline2(14x2+25x)-2(14x^2 + 25x)\newlineThe expression now looks like this:\newlinex3(x+2)2(14x2+25x)+75x^3(x + 2) - 2(14x^2 + 25x) + 75
  3. Factor Quadratic Part: We notice that there is no common factor in the second group, and the factoring by grouping does not seem to work directly. Let's try to factor the quadratic part of the expression as if it were a separate quadratic equation.\newlineThe quadratic part is x4+2x328x2x^4 + 2x^3 - 28x^2.\newlineLet's look for two numbers that multiply to give the product of the coefficient of x4x^4 (1-1) and the constant term (28-28) and add up to the coefficient of x3x^3 (22).\newlineThe numbers are 44 and 7-7 because 4×(7)=284 \times (-7) = -28 and 4+(7)=24 + (-7) = -2 (not 22, which indicates a mistake).

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