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Factor the following expression completely.

x^(4)-16x^(2)-5x^(3)+80 x-6x^(2)+96
Answer:

Factor the following expression completely.\newlinex416x25x3+80x6x2+96 x^{4}-16 x^{2}-5 x^{3}+80 x-6 x^{2}+96 \newlineAnswer:

Full solution

Q. Factor the following expression completely.\newlinex416x25x3+80x6x2+96 x^{4}-16 x^{2}-5 x^{3}+80 x-6 x^{2}+96 \newlineAnswer:
  1. Rearrange Terms: First, we need to rearrange the terms of the expression in descending order of the powers of xx.x45x316x26x2+80x+96x^4 - 5x^3 - 16x^2 - 6x^2 + 80x + 96Combine like terms.x45x322x2+80x+96x^4 - 5x^3 - 22x^2 + 80x + 96
  2. Combine Like Terms: Next, we look for common factors in groups of terms. We can group the terms as follows:\newline(x45x3)(22x280x)+96(x^4 - 5x^3) - (22x^2 - 80x) + 96\newlineNow we factor by grouping.
  3. Group and Factor: Factor out the greatest common factor from each group. x3(x5)22x(x4)+96x^3(x - 5) - 22x(x - 4) + 96
  4. Further Factorization: We notice that the expression does not have a common factor in all terms, but we can look for a pattern or factors that can be factored further. The term +96+96 seems to be out of place, so we should check if we can factor the trinomial x3(x5)22x(x4)x^3(x - 5) - 22x(x - 4) further.
  5. Correct Mistake: Let's try to factor by splitting the middle term of the quadratic part of the expression.\newlineWe are looking for two numbers that multiply to give 5×22-5 \times -22 (the coefficient of x4x^4 times the constant term of the quadratic part) and add up to give the coefficient of the xx term in the quadratic part, which is 00.\newlineHowever, we made a mistake in the previous step; the term +96+96 should have been included in the grouping. We need to correct this before proceeding.

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