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Factor completely.

27x^(4)y^(2)+37 xz^(3)
Answer:

Factor completely.\newline27x4y2+37xz3 27 x^{4} y^{2}+37 x z^{3} \newlineAnswer:

Full solution

Q. Factor completely.\newline27x4y2+37xz3 27 x^{4} y^{2}+37 x z^{3} \newlineAnswer:
  1. Identify Common Factor: Identify if there is a common factor in both terms of the expression 27x4y2+37xz327x^{4}y^{2} + 37xz^{3}. We look for a common factor in the coefficients (2727 and 3737) and the variables (x4y2x^{4}y^{2} and xz3xz^{3}).
  2. Determine Coefficients GCF: Determine the greatest common factor (GCF) of the coefficients.\newlineThe coefficients 2727 and 3737 are both prime numbers and do not share any common factors other than 11.
  3. Determine Variable GCF: Determine the GCF of the variable terms.\newlineThe variable terms x4y2x^{4}y^{2} and xz3xz^{3} share a common factor of xx. The highest power of xx that is in both terms is x1x^{1} (since xx is the same as x1x^{1}).
  4. Factor Out GCF: Factor out the GCF from the expression.\newlineThe GCF of the entire expression is xx. We factor xx out of each term to get x(27x3y2+37z3)x(27x^{3}y^{2} + 37z^{3}).
  5. Check Further Factoring: Check if the remaining terms inside the parentheses can be factored further.\newlineThe terms 27x3y227x^{3}y^{2} and 37z337z^{3} do not have any common factors, and neither of them is a perfect square or a product of squares that would allow for further factoring.
  6. Conclude Complete Factoring: Conclude that the expression is completely factored. The expression 27x4y2+37xz327x^{4}y^{2} + 37xz^{3} is completely factored as x(27x3y2+37z3)x(27x^{3}y^{2} + 37z^{3}).

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