Factor completely: 25x^(2)(4x^(2)-5)-4(4x^(2)-5) Answer:

Identify Common Factor: Identify the common factor in both terms of the expression. The common factor is (4x^(2) - 5).Factor Out Common Factor: Factor out the common factor (4x^(2) - 5) from both terms. The expression becomes (4x^(2) - 5)(25x^(2) - 4).Check Quadratic Expressions: Check if the remaining quadratic expressions can be factored further. The quadratic expressions 25x^(2) and -4 are both perfect squares, so we can factor them as a difference of squares.Factor Difference of Squares: Factor the expression 25x^(2) - 4 as a difference of squares. The factored form is (5x + 2)(5x - 2).Combine Factored Parts: Combine the factored parts to write the final completely factored expression. The final factored form is (4x^(2) - 5)(5x + 2)(5x - 2).

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Factor completely:

25x^(2)(4x^(2)-5)-4(4x^(2)-5)
Answer:

Factor completely: $\newline$ $25 x^{2}\left(4 x^{2}-5\right)-4\left(4 x^{2}-5\right)$ $\newline$ Answer:

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Precalculus

Operations with rational exponents

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Q. Factor completely:

\newline

25 x^{2}\left(4 x^{2}-5\right)-4\left(4 x^{2}-5\right)

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Answer:

Identify Common Factor: Identify the common factor in both terms of the expression. $\newline$ The common factor is $4x^{2} - 5$ .
Factor Out Common Factor: Factor out the common factor $(4x^{2} - 5)$ from both terms. $\newline$ The expression becomes $(4x^{2} - 5)(25x^{2} - 4)$ .
Check Quadratic Expressions: Check if the remaining quadratic expressions can be factored further. $\newline$ The quadratic expressions $25x^{2}$ and $-4$ are both perfect squares, so we can factor them as a difference of squares.
Factor Difference of Squares: Factor the expression $25x^{2} - 4$ as a difference of squares. $\newline$ The factored form is $(5x + 2)(5x - 2)$ .
Combine Factored Parts: Combine the factored parts to write the final completely factored expression. $\newline$ The final factored form is $(4x^{2} - 5)(5x + 2)(5x - 2)$ .