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Factor completely.

21x^(3)y^(3)z^(2)-14y^(4)z^(4)
Answer:

Factor completely.\newline21x3y3z214y4z4 21 x^{3} y^{3} z^{2}-14 y^{4} z^{4} \newlineAnswer:

Full solution

Q. Factor completely.\newline21x3y3z214y4z4 21 x^{3} y^{3} z^{2}-14 y^{4} z^{4} \newlineAnswer:
  1. Identify GCF: Identify the greatest common factor (GCF) of the two terms.\newlineThe GCF of 21x3y3z221x^{3}y^{3}z^{2} and 14y4z414y^{4}z^{4} is 7y3z27y^{3}z^{2}.
  2. Factor out GCF: Factor out the GCF from each term.\newline21x3y3z214y4z4=7y3z2(3x32y1z2)21x^{3}y^{3}z^{2} - 14y^{4}z^{4} = 7y^{3}z^{2}(3x^{3} - 2y^{1}z^{2})
  3. Check for further factorization: Check if the remaining terms inside the parentheses can be factored further.\newlineThe terms 3x33x^{3} and 2y1z22y^{1}z^{2} do not have a common factor other than 11, and they are not special products (like a difference of squares or a perfect square trinomial), so they cannot be factored further.

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