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Factor completely.

14x^(2)y^(5)z^(3)+3y^(4)
Answer:

Factor completely.\newline14x2y5z3+3y4 14 x^{2} y^{5} z^{3}+3 y^{4} \newlineAnswer:

Full solution

Q. Factor completely.\newline14x2y5z3+3y4 14 x^{2} y^{5} z^{3}+3 y^{4} \newlineAnswer:
  1. Identify GCF: Identify the greatest common factor (GCF) of the two terms in the expression 14x2y5z314x^{2}y^{5}z^{3} and 3y43y^{4}. The GCF is the largest factor that divides both terms. Since there is no common factor involving xx or zz, and the smallest power of yy in both terms is y4y^{4}, the GCF is 3y43y^{4}.
  2. Factor Out GCF: Factor out the GCF from the expression.\newlineWe write the original expression as the GCF multiplied by what is left in each term after dividing by the GCF.\newline14x2y5z3+3y4=3y4(143×x2y54z3+1)14x^{2}y^{5}z^{3} + 3y^{4} = 3y^{4}(\frac{14}{3} \times x^{2}y^{5-4}z^{3} + 1)
  3. Simplify Expression: Simplify the expression inside the parentheses.\newlineDivide 1414 by 33 and subtract the exponents of yy (54=15 - 4 = 1).\newline3y4(143×x2y54z3+1)=3y4(4x2yz3+1)3y^{4}(\frac{14}{3} \times x^{2}y^{5-4}z^{3} + 1) = 3y^{4}(4x^{2}yz^{3} + 1)
  4. Check for Factors: Check for any additional common factors or special products that could be factored further.\newlineThe expression inside the parentheses, 4x2yz3+14x^{2}yz^{3} + 1, does not have any common factors and is not a special product (such as a difference of squares or a perfect square trinomial). Therefore, the expression is fully factored.

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