f(x)=x2−6x−7Which of the following is an equivalent form of the function f in which the zeros of f appear as constants or coefficients?Choose 1 answer:(A) f(x)=(x−7)(x+1)(B) f(x)=(x−1)(x+7)(C) f(x)=x(x−6)−7(D) f(x)=(x−6)2−7
Q. f(x)=x2−6x−7Which of the following is an equivalent form of the function f in which the zeros of f appear as constants or coefficients?Choose 1 answer:(A) f(x)=(x−7)(x+1)(B) f(x)=(x−1)(x+7)(C) f(x)=x(x−6)−7(D) f(x)=(x−6)2−7
Find Zeros: To find an equivalent form of the function that shows the zeros, we need to factor the quadratic equationf(x)=x2−6x−7.We look for two numbers that multiply to −7 and add up to −6.The numbers −7 and +1 satisfy these conditions because (−7)×(+1)=−7 and (−7)+(+1)=−6.
Factor Quadratic Equation: We use these numbers to factor the quadratic equation:f(x) = x2−6x−7f(x) = (x−7)(x+1)This is the factored form of the quadratic equation, which reveals the zeros of the function.
Compare with Answer Choices: We compare the factored form with the given answer choices to find the matching one.(A) f(x)=(x−7)(x+1) matches the factored form we found in Step 2.
Compare with Answer Choices: We compare the factored form with the given answer choices to find the matching one.(A) f(x)=(x−7)(x+1) matches the factored form we found in Step 2.We check the other answer choices to confirm that they do not match the factored form we found:(B) f(x)=(x−1)(x+7) does not match because it would expand to x2+6x−7.(C) f(x)=x(x−6)−7 does not match because it would expand to x2−6x−7, but does not show the zeros as constants or coefficients.(D) f(x)=(x−6)2−7 does not match because it would expand to x2−12x+36−7.
More problems from Compare linear and exponential growth