f(x)={[(x+1)^(2)-3," for ",x = 4]:} Find f(2) Answer:

Define Function: The function f(x) is defined piecewise, with one expression for x = 4. We need to determine which expression to use for x = 2.Check x=2: Since 2 is not less than or equal to -1 and not greater than or equal to 4, it does not fall within the range of either piece of the piecewise function. Therefore, f(2) is not defined by the given function.Conclusion: We conclude that f(2) does not have a value based on the given piecewise function, as 2 does not satisfy the conditions for either piece of the function.

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$f(x)={[(x+1)^(2)-3," for ",x <= -1],[x-8," for ",x >= 4]:} Find f(2) Answer:$

$f(x)=\left\{\begin{array}{lll} (x+1)^{2}-3 & \text { for } & x \leq-1 \\ x-8 & \text { for } & x \geq 4 \end{array}\right.$ $\newline$ Find $f(2)$ $\newline$ Answer: $\newline$

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Precalculus

Simplify radical expressions with variables

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f(x)=\left\{\begin{array}{lll} (x+1)^{2}-3 & \text { for } & x \leq-1 \\ x-8 & \text { for } & x \geq 4 \end{array}\right.

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Find

f(2)

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Answer:

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Define Function: The function $f(x)$ is defined piecewise, with one expression for $x \leq -1$ and another for $x \geq 4$ . We need to determine which expression to use for $x = 2$ .
Check $x=2$ : Since $2$ is not less than or equal to $-1$ and not greater than or equal to $4$ , it does not fall within the range of either piece of the piecewise function. Therefore, $f(2)$ is not defined by the given function.
Conclusion: We conclude that $f(2)$ does not have a value based on the given piecewise function, as $2$ does not satisfy the conditions for either piece of the function.