Q. f(x)=2x+3g(x)=x2−3x+1Write g(f(x)) as an expression in terms of x.g(f(x))=
Identify functions: Identify the functions to be composed.We have two functions:f(x)=2x+3g(x)=x2−3x+1We need to find the composition of g(f(x)), which means we will substitute f(x) into g(x).
Substitute f(x) into g(x): Substitute f(x) into g(x). To find g(f(x)), we replace every instance of x in g(x) with the expression for f(x). So, g(f(x))=(2x+3)2−3(2x+3)+1
Expand (2x+3)2: Expand the expression (2x+3)2.(2x+3)2=(2x+3)(2x+3)=4x2+6x+6x+9=4x2+12x+9
Distribute −3: Distribute the −3 across the terms in the parentheses.−3(2x+3)=−6x−9
Combine terms: Combine all the terms to get the final expression for g(f(x)).g(f(x))=4x2+12x+9−6x−9+1
Simplify expression: Simplify the expression by combining like terms.g(f(x))=4x2+(12x−6x)+(9−9+1)g(f(x))=4x2+6x+1
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