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Distribute to create an equivalent expression with the fewest symbols possible.
1
2
(
10
x
+
20
y
+
10
z
)
=
\dfrac{1}{2}(10x + 20y +10z) =
2
1
(
10
x
+
20
y
+
10
z
)
=
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Math Problems
Algebra 2
Csc, sec, and cot of special angles
Full solution
Q.
Distribute to create an equivalent expression with the fewest symbols possible.
1
2
(
10
x
+
20
y
+
10
z
)
=
\dfrac{1}{2}(10x + 20y +10z) =
2
1
(
10
x
+
20
y
+
10
z
)
=
Question Prompt:
Question_prompt: What is the simplified expression for
1
2
(
10
x
+
20
y
+
10
z
)
\dfrac{1}{2}(10x + 20y + 10z)
2
1
(
10
x
+
20
y
+
10
z
)
?
Multiply Terms by
1
1
1
/
2
2
2
:
Multiply each term inside the parentheses by
1
2
\dfrac{1}{2}
2
1
.
\newline
1
2
⋅
10
x
=
5
x
\dfrac{1}{2} \cdot 10x = 5x
2
1
⋅
10
x
=
5
x
\newline
1
2
⋅
20
y
=
10
y
\dfrac{1}{2} \cdot 20y = 10y
2
1
⋅
20
y
=
10
y
\newline
1
2
⋅
10
z
=
5
z
\dfrac{1}{2} \cdot 10z = 5z
2
1
⋅
10
z
=
5
z
Combine Results:
Combine the results to get the simplified expression.
\newline
5
x
+
10
y
+
5
z
5x + 10y + 5z
5
x
+
10
y
+
5
z
More problems from Csc, sec, and cot of special angles
Question
Marco's class is painting a mural on the side of their school. The mural covers a
3
1
2
m
3 \frac{1}{2} \mathrm{~m}
3
2
1
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high, rectangular wall. It has an area of
28
m
2
28 \mathrm{~m}^{2}
28
m
2
.
\newline
What is the length of the mural?
\newline
m
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Question
A cup of hot coffee has been left to cool in a room with an ambient temperature of
2
1
∘
C
21^{\circ} \mathrm{C}
2
1
∘
C
.
\newline
The relationship between the elapsed time,
m
m
m
, in minutes, since the coffee was left to cool, and the temperature of the coffee,
T
T
T
, measured in
∘
C
{ }^{\circ} \mathrm{C}
∘
C
, is modeled by the following function.
\newline
T
(
m
)
=
21
+
74
⋅
1
0
−
0.03
m
T(m)=21+74 \cdot 10^{-0.03 m}
T
(
m
)
=
21
+
74
⋅
1
0
−
0.03
m
\newline
What will the temperature of the coffee be after
10
10
10
minutes?
\newline
Round your answer, if necessary, to the nearest hundredth.
\newline
∘
C
{ }^{\circ} C
∘
C
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Posted 10 months ago
Question
Takumi plants a tree in his backyard and studies how the number of branches grows over time.
\newline
He predicts that the relationship between
N
N
N
, the number of branches on the tree, and
t
t
t
, the elapsed time, in years, since the tree was planted can be modeled by the following equation.
\newline
N
=
5
⋅
1
0
0.3
t
N=5 \cdot 10^{0.3 t}
N
=
5
⋅
1
0
0.3
t
\newline
According to Takumi's model, in how many years will the tree have
100
100
100
branches?
\newline
Give an exact answer expressed as a base
−
10
-10
−
10
logarithm.
\newline
years
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Posted 10 months ago
Question
Let
g
(
x
)
=
2
x
g(x)=2^{x}
g
(
x
)
=
2
x
.
\newline
Can we use the mean value theorem to say the equation
g
′
(
x
)
=
16
g^{\prime}(x)=16
g
′
(
x
)
=
16
has a solution where
3
<
x
<
5
3<x<5
3
<
x
<
5
?
\newline
Choose
1
1
1
answer:
\newline
(A) No, since the function is not differentiable on that interval.
\newline
(B) No, since the average rate of change of
g
g
g
over the interval
3
≤
x
≤
5
3 \leq x \leq 5
3
≤
x
≤
5
isn't equal to
1
6
‾
1 \overline{6}
1
6
.
\newline
(C) Yes, both conditions for using the mean value theorem have been met.
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Posted 9 months ago
Question
d
d
x
(
3
x
2
−
1
x
−
2
)
=
\frac{d}{d x}\left(\frac{3 x^{2}-1}{x-2}\right)=
d
x
d
(
x
−
2
3
x
2
−
1
)
=
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Posted 9 months ago
Question
d
y
d
t
=
2
t
+
3
and
y
(
1
)
=
6
\frac{d y}{d t}=2 t+3 \text { and } y(1)=6
d
t
d
y
=
2
t
+
3
and
y
(
1
)
=
6
\newline
What is
t
t
t
when
y
=
0
y=0
y
=
0
?
\newline
Choose all answers that apply:
\newline
(A)
t
=
−
1
t=-1
t
=
−
1
\newline
(B)
t
=
−
3
t=-3
t
=
−
3
\newline
(C)
t
=
0
t=0
t
=
0
\newline
(D)
t
=
−
4
t=-4
t
=
−
4
\newline
(E)
t
=
1
t=1
t
=
1
\newline
(F)
t
=
−
2
t=-2
t
=
−
2
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Question
d
d
x
(
x
3
4
)
=
\frac{d}{d x}\left(x^{\frac{3}{4}}\right)=
d
x
d
(
x
4
3
)
=
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Posted 9 months ago
Question
y
=
x
13
y=x^{13}
y
=
x
13
\newline
d
y
d
x
=
\frac{d y}{d x}=
d
x
d
y
=
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Posted 9 months ago
Question
y
=
x
10
y=x^{10}
y
=
x
10
\newline
d
y
d
x
=
\frac{d y}{d x}=
d
x
d
y
=
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Posted 9 months ago
Question
d
d
x
[
x
6
]
=
\frac{d}{d x}\left[x^{6}\right]=
d
x
d
[
x
6
]
=
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Posted 9 months ago
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