Q. D=⎣⎡−1210−23⎦⎤ and F=[032−2]Let H=DF. Find H.H=
Define Matrices D and F: Define the matrices D and F.Matrix D is a 3×2 matrix, and matrix F is a 2×2 matrix.D=[−1amp;02amp;−21amp;3]F=[0amp;23amp;−2]
Verify Multiplication Possibility: Verify if the multiplication of D and F is possible.The number of columns in the first matrix (D) must be equal to the number of rows in the second matrix (F) to multiply them. D has 2 columns, and F has 2 rows, so multiplication is possible.
Set Up Matrix Multiplication: Set up the multiplication of matrices D and F. To multiply the matrices, we take the dot product of the rows of D with the columns of F. This will result in a new matrix H which will have the same number of rows as D and the same number of columns as F.
Calculate First Element of H: Calculate the first element of matrix H. Multiply the first row of D by the first column of F. H[1,1]=(−1×0)+(0×3)=0
Calculate Second Element of First Row: Calculate the second element of the first row of matrix H. Multiply the first row of D by the second column of F. H[1,2]=(−1×2)+(0×−2)=−2
Calculate First Element of Second Row: Calculate the first element of the second row of matrix H. Multiply the second row of D by the first column of F. H[2,1]=(2×0)+(−2×3)=−6
Calculate Second Element of Second Row: Calculate the second element of the second row of matrix H. Multiply the second row of D by the second column of F. H[2,2]=(2×2)+(−2×−2)=4+4=8
Calculate First Element of Third Row: Calculate the first element of the third row of matrix H. Multiply the third row of D by the first column of F. H[3,1]=(1×0)+(3×3)=9
Calculate Second Element of Third Row: Calculate the second element of the third row of matrix H. Multiply the third row of D by the second column of F. H[3,2]=(1×2)+(3×−2)=2−6=−4
Combine Elements to Form H: Combine the elements to form the matrix H.H=[0amp;−2−6amp;89amp;−4]
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