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D=[[-1,0],[2,-2],[1,3]] and

F=[[0,2],[3,-2]]
Let 
H=DF. Find 
H.

H=

D=[1amp;02amp;21amp;3] \mathrm{D}=\left[\begin{array}{rr}-1 & 0 \\ 2 & -2 \\ 1 & 3\end{array}\right] and F=[0amp;23amp;2] F=\left[\begin{array}{rr} 0 & 2 \\ 3 & -2 \end{array}\right] \newlineLet H=DF \mathrm{H}=\mathrm{DF} . Find H \mathrm{H} .\newlineH= \mathbf{H}=

Full solution

Q. D=[102213] \mathrm{D}=\left[\begin{array}{rr}-1 & 0 \\ 2 & -2 \\ 1 & 3\end{array}\right] and F=[0232] F=\left[\begin{array}{rr} 0 & 2 \\ 3 & -2 \end{array}\right] \newlineLet H=DF \mathrm{H}=\mathrm{DF} . Find H \mathrm{H} .\newlineH= \mathbf{H}=
  1. Define Matrices DD and FF: Define the matrices DD and FF.\newlineMatrix DD is a 3×23 \times 2 matrix, and matrix FF is a 2×22 \times 2 matrix.\newlineD=[1amp;0 2amp;2 1amp;3]D = \left[\begin{array}{cc}-1 & 0 \ 2 & -2 \ 1 & 3\end{array}\right]\newlineF=[0amp;2 3amp;2]F = \left[\begin{array}{cc}0 & 2 \ 3 & -2\end{array}\right]
  2. Verify Multiplication Possibility: Verify if the multiplication of DD and FF is possible.\newlineThe number of columns in the first matrix (DD) must be equal to the number of rows in the second matrix (FF) to multiply them. DD has 22 columns, and FF has 22 rows, so multiplication is possible.
  3. Set Up Matrix Multiplication: Set up the multiplication of matrices DD and FF. To multiply the matrices, we take the dot product of the rows of DD with the columns of FF. This will result in a new matrix HH which will have the same number of rows as DD and the same number of columns as FF.
  4. Calculate First Element of H: Calculate the first element of matrix HH. Multiply the first row of DD by the first column of FF. H[1,1]=(1×0)+(0×3)=0H[1,1] = (-1 \times 0) + (0 \times 3) = 0
  5. Calculate Second Element of First Row: Calculate the second element of the first row of matrix HH. Multiply the first row of DD by the second column of FF. H[1,2]=(1×2)+(0×2)=2H[1,2] = (-1 \times 2) + (0 \times -2) = -2
  6. Calculate First Element of Second Row: Calculate the first element of the second row of matrix HH. Multiply the second row of DD by the first column of FF. H[2,1]=(2×0)+(2×3)=6H[2,1] = (2 \times 0) + (-2 \times 3) = -6
  7. Calculate Second Element of Second Row: Calculate the second element of the second row of matrix HH. Multiply the second row of DD by the second column of FF. H[2,2]=(2×2)+(2×2)=4+4=8H[2,2] = (2 \times 2) + (-2 \times -2) = 4 + 4 = 8
  8. Calculate First Element of Third Row: Calculate the first element of the third row of matrix HH. Multiply the third row of DD by the first column of FF. H[3,1]=(1×0)+(3×3)=9H[3,1] = (1 \times 0) + (3 \times 3) = 9
  9. Calculate Second Element of Third Row: Calculate the second element of the third row of matrix HH. Multiply the third row of DD by the second column of FF. H[3,2]=(1×2)+(3×2)=26=4H[3,2] = (1 \times 2) + (3 \times -2) = 2 - 6 = -4
  10. Combine Elements to Form H: Combine the elements to form the matrix HH.H=[0amp;2 6amp;8 9amp;4]H = \begin{bmatrix} 0 & -2 \ -6 & 8 \ 9 & -4 \end{bmatrix}

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