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Consider the following problem:$\newline$The velocity of a pendulum changes at a rate of $a(t)=0.9^{t} \cos (0.2 t)$ meters per second squared (where $t$ is the time in seconds). At time $t=6$, the velocity of the pendulum is $0$.$8$ meters per second. By how much does the velocity change between $t=6$ and $t=12$ seconds?$\newline$Which expression can we use to solve the problem?$\newline$Choose $1$ answer:$\newline$(A) $a^{\prime}(6)+0.8$$\newline$(B) $a^{\prime}(12)$$\newline$(C) $a^{\prime}(12)-a^{\prime}(6)$$\newline$(D) $\int_{6}^{12} a(t) d t$