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Consider the following problem:
The number of people in a cafeteria is changing at a rate of 
r(t)=1920-160 t people per hour (where 
t is the time in hours). At time 
t=11.5, there were 60 people in the cafeteria. How many people were in the cafeteria at hour 12.5 ?
Which expression can we use to solve the problem?
Choose 1 answer:
(A) 
int_(11.5)^(12.5)r^(')(t)dt
(B) 
60+int_(11.5)^(12.5)r^(')(t)dt
(C) 
int_(11.5)^(12.5)r(t)dt
(D) 
60+int_(11.5)^(12.5)r(t)dt

Consider the following problem:\newlineThe number of people in a cafeteria is changing at a rate of r(t)=1920160t r(t)=1920-160 t people per hour (where t t is the time in hours). At time t=11.5 t=11.5 , there were 6060 people in the cafeteria. How many people were in the cafeteria at hour 1212.55 ?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) 11.512.5r(t)dt \int_{11.5}^{12.5} r^{\prime}(t) d t \newline(B) 60+11.512.5r(t)dt 60+\int_{11.5}^{12.5} r^{\prime}(t) d t \newline(C) 11.512.5r(t)dt \int_{11.5}^{12.5} r(t) d t \newline(D) 60+11.512.5r(t)dt 60+\int_{11.5}^{12.5} r(t) d t

Full solution

Q. Consider the following problem:\newlineThe number of people in a cafeteria is changing at a rate of r(t)=1920160t r(t)=1920-160 t people per hour (where t t is the time in hours). At time t=11.5 t=11.5 , there were 6060 people in the cafeteria. How many people were in the cafeteria at hour 1212.55 ?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) 11.512.5r(t)dt \int_{11.5}^{12.5} r^{\prime}(t) d t \newline(B) 60+11.512.5r(t)dt 60+\int_{11.5}^{12.5} r^{\prime}(t) d t \newline(C) 11.512.5r(t)dt \int_{11.5}^{12.5} r(t) d t \newline(D) 60+11.512.5r(t)dt 60+\int_{11.5}^{12.5} r(t) d t
  1. Understand the problem: Understand the problem.\newlineWe are given the rate of change of the number of people in the cafeteria, r(t)r(t), and the number of people at a specific time, t=11.5t=11.5 hours. We need to find the number of people at t=12.5t=12.5 hours.
  2. Determine the expression: Determine the expression to use.\newlineTo find the number of people at t=12.5t=12.5 hours, we need to integrate the rate of change from t=11.5t=11.5 to t=12.5t=12.5 and add it to the number of people at t=11.5t=11.5.
  3. Identify the correct integral expression: Identify the correct integral expression.\newlineThe correct expression to calculate the number of people at t=12.5t=12.5 is the integral of the rate of change from t=11.5t=11.5 to t=12.5t=12.5 plus the initial number of people at t=11.5t=11.5. This corresponds to option (D) 60+11.512.5r(t)dt60 + \int_{11.5}^{12.5}r(t)\,dt.
  4. Calculate the integral: Calculate the integral.\newlineWe need to integrate r(t)=1920160tr(t) = 1920 - 160t from t=11.5t=11.5 to t=12.5t=12.5.\newline11.512.5(1920160t)dt=[1920t80t2]11.512.5\int_{11.5}^{12.5}(1920 - 160t)dt = [1920t - 80t^2]_{11.5}^{12.5}\newline=(192012.580(12.5)2)(192011.580(11.5)2)= (1920\cdot12.5 - 80\cdot(12.5)^2) - (1920\cdot11.5 - 80\cdot(11.5)^2)\newline=(2400080156.25)(2208080132.25)= (24000 - 80\cdot156.25) - (22080 - 80\cdot132.25)\newline=(2400012500)(2208010580)= (24000 - 12500) - (22080 - 10580)\newline=1150011500= 11500 - 11500\newline=0= 0

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