Consider the following problem:The number of people in a cafeteria is changing at a rate of r(t)=1920−160t people per hour (where t is the time in hours). At time t=11.5, there were 60 people in the cafeteria. How many people were in the cafeteria at hour 12.5 ?Which expression can we use to solve the problem?Choose 1 answer:(A) ∫11.512.5r′(t)dt(B) 60+∫11.512.5r′(t)dt(C) ∫11.512.5r(t)dt(D) 60+∫11.512.5r(t)dt
Q. Consider the following problem:The number of people in a cafeteria is changing at a rate of r(t)=1920−160t people per hour (where t is the time in hours). At time t=11.5, there were 60 people in the cafeteria. How many people were in the cafeteria at hour 12.5 ?Which expression can we use to solve the problem?Choose 1 answer:(A) ∫11.512.5r′(t)dt(B) 60+∫11.512.5r′(t)dt(C) ∫11.512.5r(t)dt(D) 60+∫11.512.5r(t)dt
Understand the problem: Understand the problem.We are given the rate of change of the number of people in the cafeteria, r(t), and the number of people at a specific time, t=11.5 hours. We need to find the number of people at t=12.5 hours.
Determine the expression: Determine the expression to use.To find the number of people at t=12.5 hours, we need to integrate the rate of change from t=11.5 to t=12.5 and add it to the number of people at t=11.5.
Identify the correct integral expression: Identify the correct integral expression.The correct expression to calculate the number of people at t=12.5 is the integral of the rate of change from t=11.5 to t=12.5 plus the initial number of people at t=11.5. This corresponds to option (D) 60+∫11.512.5r(t)dt.
Calculate the integral: Calculate the integral.We need to integrate r(t)=1920−160t from t=11.5 to t=12.5.∫11.512.5(1920−160t)dt=[1920t−80t2]11.512.5=(1920⋅12.5−80⋅(12.5)2)−(1920⋅11.5−80⋅(11.5)2)=(24000−80⋅156.25)−(22080−80⋅132.25)=(24000−12500)−(22080−10580)=11500−11500=0
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