Consider the equation−16⋅106x=−80. Solve the equation for x. Express the solution as a logarithm in base10.x=Approximate the value of x. Round your answer to the nearest thousandth.x≈
Q. Consider the equation−16⋅106x=−80. Solve the equation for x. Express the solution as a logarithm in base10.x=Approximate the value of x. Round your answer to the nearest thousandth.x≈
Isolate exponential term: First, let's isolate the exponential term by dividing both sides by -16").\(\newline\$-16\cdot10^{(6x)} = -80\)\(\newline\)\(10^{(6x)} = \frac{-80}{-16}\)\(\newline\)\(10^{(6x)} = 5\)
Take logarithm: Now, we'll take the logarithm of both sides to solve for \(6x\).\[\log(10^{6x}) = \log(5)\]\[6x = \log(5)\]
Divide by \(6\): Next, we divide both sides by \(6\) to solve for \(x\).\[x = \frac{\log(5)}{6}\]
Calculate approximate value: Finally, we'll use a calculator to approximate the value of \(x\).\(\newline\)\(x \approx \log(5) / 6\)\(\newline\)\(x \approx 0.1139\) (rounded to the nearest thousandth)
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