Chun was asked whether the following equation is an identity:3(2x−1)2+27=36x2−36x+36He performed the following steps:3(2x−1)2+27↪ Step 1=3(2x−1)(2x−1)+27↪ Step 2=(6x−3)(6x−3)+27↪ Step 3=36x2−18x−18x+9+27↪ Step 4=36x2−36x+36For this reason, Chun stated that the equation is a true identity.Is Chun correct? If not, in which step did he make a mistake?Choose 1 answer:(A) Chun is correct.(B) Chun is incorrect. He made a mistake in step 2.(C) Chun is incorrect. He made a mistake in step 3.(D) Chun is incorrect. He made a mistake in step 4.
Q. Chun was asked whether the following equation is an identity:3(2x−1)2+27=36x2−36x+36He performed the following steps:3(2x−1)2+27↪ Step 1=3(2x−1)(2x−1)+27↪ Step 2=(6x−3)(6x−3)+27↪ Step 3=36x2−18x−18x+9+27↪ Step 4=36x2−36x+36For this reason, Chun stated that the equation is a true identity.Is Chun correct? If not, in which step did he make a mistake?Choose 1 answer:(A) Chun is correct.(B) Chun is incorrect. He made a mistake in step 2.(C) Chun is incorrect. He made a mistake in step 3.(D) Chun is incorrect. He made a mistake in step 4.
Expand Binomial: Expand the squared binomial. 3(2x−1)2+27=3(4x2−4x+1)+27
Distribute and Add: Distribute the 3 into the binomial and add 27. = 12x2−12x+3+27
Combine Like Terms: Combine like terms.=12x2−12x+30
Compare Equations: Compare the expanded equation to the original equation.12x2−12x+30=36x2−36x+36
More problems from Transformations of quadratic functions