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Solve the equation below for $x$ in terms of $a$ . $\newline$ $4(ax+3)-3ax = 25+3a$

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Compare linear and exponential growth

Full solution

Q. Solve the equation below for

x

in terms of

a

.

\newline

4(ax+3)-3ax = 25+3a

Expand Equation: Expand the left side of the equation. $\newline$ We have the equation $4(ax + 3) - 3ax = 25 + 3a$ . Let's distribute the $4$ into the parentheses: $\newline$ $4 \cdot ax + 4 \cdot 3 - 3ax = 25 + 3a$ $\newline$ $4ax + 12 - 3ax = 25 + 3a$
Combine Like Terms: Combine like terms on the left side of the equation. $\newline$ Now we combine the terms with $ax$ : $\newline$ $(4ax - 3ax) + 12 = 25 + 3a$ $\newline$ $1ax + 12 = 25 + 3a$
Isolate x Term: Subtract $12$ from both sides of the equation to isolate the term with $x$ . $\newline$ $ax + 12 - 12 = 25 + 3a - 12$ $\newline$ $ax = 13 + 3a$
Solve for x: Divide both sides by $a$ to solve for $x$ . $\frac{ax}{a} = \frac{13 + 3a}{a}$ $x = \frac{13}{a} + 3$

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Question

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