Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), t seconds after Amir threw it, is modeled by How many seconds after being thrown will the ball reach its maximum height? t seconds
Q. Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), t seconds after Amir threw it, is modeled by How many seconds after being thrown will the ball reach its maximum height? t seconds
Identify Quadratic Equation: Identify the general form of the quadratic equation for the ball's height.The general form of the quadratic equation for projectile motion is h(t)=−gt2+vt+h0, where h(t) is the height of the ball at time t, g is the acceleration due to gravity, v is the initial velocity, and h0 is the initial height from which the ball is thrown.
Determine Maximum Height Time: Determine the time at which the ball reaches its maximum height. The maximum height is reached at the vertex of the parabola represented by the quadratic equation. The time at which the vertex occurs, tvertex, can be found using the formula tvertex=−2ab, where a is the coefficient of t2 and b is the coefficient of t in the quadratic equation.
Apply Formula for Maximum Height Time: Apply the formula to find the time of maximum height. Since we do not have the specific values for a and b, we cannot calculate the exact time. However, if the equation were provided, we would plug in the values for a and b to find tvertex.
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