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Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), tt seconds after Amir threw it, is modeled by How many seconds after being thrown will the ball reach its maximum height? tt seconds

Full solution

Q. Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), tt seconds after Amir threw it, is modeled by How many seconds after being thrown will the ball reach its maximum height? tt seconds
  1. Identify Quadratic Equation: Identify the general form of the quadratic equation for the ball's height.\newlineThe general form of the quadratic equation for projectile motion is h(t)=gt2+vt+h0h(t) = -gt^2 + vt + h_0, where h(t)h(t) is the height of the ball at time tt, gg is the acceleration due to gravity, vv is the initial velocity, and h0h_0 is the initial height from which the ball is thrown.
  2. Determine Maximum Height Time: Determine the time at which the ball reaches its maximum height. The maximum height is reached at the vertex of the parabola represented by the quadratic equation. The time at which the vertex occurs, tvertext_{\text{vertex}}, can be found using the formula tvertex=b2at_{\text{vertex}} = -\frac{b}{2a}, where aa is the coefficient of t2t^2 and bb is the coefficient of tt in the quadratic equation.
  3. Apply Formula for Maximum Height Time: Apply the formula to find the time of maximum height. Since we do not have the specific values for aa and bb, we cannot calculate the exact time. However, if the equation were provided, we would plug in the values for aa and bb to find tvertext_{\text{vertex}}.

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