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A particle moves along a straight line. Its speed is inversely proportional to the square of the distance, 
S, it has traveled.
Which equation describes this relationship?
Choose 1 answer:
(A) 
(dS)/(dt)=(k)/(t^(2))
(B) 
S(t)=(k)/(t^(2))
(c) 
(dS)/(dt)=(k)/(S^(2))
(D) 
S(t)=(k)/(S^(2))

A particle moves along a straight line. Its speed is inversely proportional to the square of the distance, S S , it has traveled.\newlineWhich equation describes this relationship?\newlineChoose 11 answer:\newline(A) dSdt=kt2 \frac{d S}{d t}=\frac{k}{t^{2}} \newline(B) S(t)=kt2 S(t)=\frac{k}{t^{2}} \newline(c) dSdt=kS2 \frac{d S}{d t}=\frac{k}{S^{2}} \newline(D) S(t)=kS2 S(t)=\frac{k}{S^{2}}

Full solution

Q. A particle moves along a straight line. Its speed is inversely proportional to the square of the distance, S S , it has traveled.\newlineWhich equation describes this relationship?\newlineChoose 11 answer:\newline(A) dSdt=kt2 \frac{d S}{d t}=\frac{k}{t^{2}} \newline(B) S(t)=kt2 S(t)=\frac{k}{t^{2}} \newline(c) dSdt=kS2 \frac{d S}{d t}=\frac{k}{S^{2}} \newline(D) S(t)=kS2 S(t)=\frac{k}{S^{2}}
  1. Identify Relationship: Identify the relationship between speed and distance.\newlineSince the speed is inversely proportional to the square of the distance, we can write this relationship as:\newlineSpeed = k/S2k / S^{2}, where kk is a constant of proportionality.
  2. Translate into Equation: Translate the relationship into a differential equation.\newlineThe speed of the particle is the derivative of the distance with respect to time, which can be written as dSdt\frac{dS}{dt}. Therefore, we can express the relationship as:\newlinedSdt=kS2\frac{dS}{dt} = \frac{k}{S^2}
  3. Match to Options: Match the relationship to the given options.\newlineWe need to find the option that correctly represents the relationship dSdt=kS2\frac{dS}{dt} = \frac{k}{S^2}. Let's compare this to the given options:\newline(A) dSdt=kt2\frac{dS}{dt}=\frac{k}{t^{2}} - This option suggests that speed is inversely proportional to the square of time, which is not the relationship we have.\newline(B) S(t)=kt2S(t)=\frac{k}{t^{2}} - This option suggests that the distance itself is inversely proportional to the square of time, which is not the relationship we have.\newline(C) dSdt=kS2\frac{dS}{dt}=\frac{k}{S^{2}} - This option matches our relationship exactly.\newline(D) S(t)=kS2S(t)=\frac{k}{S^{2}} - This option is not meaningful, as it suggests that distance is inversely proportional to the square of itself.

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