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A mouse has made holes in opposite corners of a rectangular kitchen. Starting from its hole in the northwest corner, the mouse scurries $20$ feet along the length of the kitchen to reach a piece of cheese in the southwest corner. Then the mouse scurries $15$ feet along the width of the kitchen to its other hole in the southeast corner. Finally the mouse scurries back to the first hole. What is the total distance the mouse scurries? $\newline$ _____ feet

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Pythagorean theorem

Full solution

Q. A mouse has made holes in opposite corners of a rectangular kitchen. Starting from its hole in the northwest corner, the mouse scurries

20

feet along the length of the kitchen to reach a piece of cheese in the southwest corner. Then the mouse scurries

15

feet along the width of the kitchen to its other hole in the southeast corner. Finally the mouse scurries back to the first hole. What is the total distance the mouse scurries?

\newline

_____ feet

Mouse movement along kitchen: The mouse scurries $20$ feet along the length of the kitchen.
Total distance calculation: Then the mouse scurries $15$ feet along the width.
Total distance calculation: Then the mouse scurries $15$ feet along the width.The mouse returns to the first hole, so it scurries the length and width again, that's another $20$ feet and $15$ feet.
Total distance calculation: Then the mouse scurries $15$ feet along the width.The mouse returns to the first hole, so it scurries the length and width again, that's another $20$ feet and $15$ feet.Add up all the distances: $20$ feet + $15$ feet + $20$ feet + $15$ feet.
Total distance calculation: Then the mouse scurries $15$ feet along the width.The mouse returns to the first hole, so it scurries the length and width again, that's another $20$ feet and $15$ feet.Add up all the distances: $20$ feet + $15$ feet + $20$ feet + $15$ feet.The total distance is $20 + 15 + 20 + 15 = 70$ feet.

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