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A circle in the xyxy-plane has the equation x2+y2+ax+by+c=0x^2 + y^2 + ax + by + c = 0. What is the center of the circle?

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Q. A circle in the xyxy-plane has the equation x2+y2+ax+by+c=0x^2 + y^2 + ax + by + c = 0. What is the center of the circle?
  1. Identify Standard Form: Identify the standard form of the circle equation and compare it with the given equation.\newlineStandard form: (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2\newlineGiven equation: x2+y2=36x^2 + y^2 = 36\newlineRewrite as: (x0)2+(y0)2=36(x - 0)^2 + (y - 0)^2 = 36
  2. Determine Values: Determine the values of hh and kk from the comparison.\newlineFrom the rewritten equation, h=0h = 0 and k=0k = 0.
  3. Conclude Center: Conclude the center of the circle based on values of hh and kk. The center of the circle is (h,k)=(0,0)(h, k) = (0, 0).

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