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A car travels at 
54km//h for first 
20s,36km//h for next 
30s and finally 18 
km//h for next 
10s. Find its average speed.

A car travels at 54km/h54\,\text{km/h} for first 20s20\,\text{s}, 36km/h36\,\text{km/h} for next 30s30\,\text{s} and finally 18km/h18\,\text{km/h} for next 10s10\,\text{s}. Find its average speed.

Full solution

Q. A car travels at 54km/h54\,\text{km/h} for first 20s20\,\text{s}, 36km/h36\,\text{km/h} for next 30s30\,\text{s} and finally 18km/h18\,\text{km/h} for next 10s10\,\text{s}. Find its average speed.
  1. Convert to m/s: First, we need to convert the speeds from km/h to m/s because the time is given in seconds. To convert km/h to m/s, we divide by 3.63.6. \newline54km/h=543.6m/s54 \, \text{km/h} = \frac{54}{3.6} \, \text{m/s}\newline36km/h=363.6m/s36 \, \text{km/h} = \frac{36}{3.6} \, \text{m/s}\newline18km/h=183.6m/s18 \, \text{km/h} = \frac{18}{3.6} \, \text{m/s}
  2. Calculate speeds: Now, let's calculate the speeds in m/s.\newline5454 km/h = 1515 m/s\newline3636 km/h = 1010 m/s\newline1818 km/h = 55 m/s
  3. Calculate distances: Next, we calculate the distance covered at each speed.\newlineDistance = Speed ×\times Time\newlineFor the first speed:\newlineDistance1_1 = 1515 m/s ×\times 2020 s\newlineFor the second speed:\newlineDistance2_2 = 1010 m/s ×\times 3030 s\newlineFor the third speed:\newlineDistance3_3 = 1_100 m/s ×\times 1010 s
  4. Perform distance calculations: Now, let's perform the calculations for the distances.\newlineDistance11 = 15m/s×20s=300m15 \, \text{m/s} \times 20 \, \text{s} = 300 \, \text{m}\newlineDistance22 = 10m/s×30s=300m10 \, \text{m/s} \times 30 \, \text{s} = 300 \, \text{m}\newlineDistance33 = 5m/s×10s=50m5 \, \text{m/s} \times 10 \, \text{s} = 50 \, \text{m}
  5. Find total distance: We add up the distances to find the total distance covered.\newlineTotal distance =Distance1+Distance2+Distance3= \text{Distance}_1 + \text{Distance}_2 + \text{Distance}_3\newlineTotal distance =300m+300m+50m= 300 \, \text{m} + 300 \, \text{m} + 50 \, \text{m}
  6. Find total time: Let's calculate the total distance.\newlineTotal distance = 300m+300m+50m=650m300\,\text{m} + 300\,\text{m} + 50\,\text{m} = 650\,\text{m}
  7. Calculate average speed: Now, we need to find the total time taken for the journey.\newlineTotal time =Time1+Time2+Time3= \text{Time}_1 + \text{Time}_2 + \text{Time}_3\newlineTotal time =20s+30s+10s= 20 \, \text{s} + 30 \, \text{s} + 10 \, \text{s}
  8. Calculate average speed: Now, we need to find the total time taken for the journey.\newlineTotal time = Time11 + Time22 + Time33\newlineTotal time = 20s+30s+10s20 \, \text{s} + 30 \, \text{s} + 10 \, \text{s}Let's calculate the total time.\newlineTotal time = 20s+30s+10s=60s20 \, \text{s} + 30 \, \text{s} + 10 \, \text{s} = 60 \, \text{s}
  9. Calculate average speed: Now, we need to find the total time taken for the journey.\newlineTotal time = Time11 + Time22 + Time33\newlineTotal time = 20s+30s+10s20 \, \text{s} + 30 \, \text{s} + 10 \, \text{s}Let's calculate the total time.\newlineTotal time = 20s+30s+10s=60s20 \, \text{s} + 30 \, \text{s} + 10 \, \text{s} = 60 \, \text{s}Finally, we calculate the average speed using the total distance and total time.\newlineAverage speed = Total distance / Total time\newlineAverage speed = 650m/60s650 \, \text{m} / 60 \, \text{s}
  10. Calculate average speed: Now, we need to find the total time taken for the journey.\newlineTotal time = Time11 + Time22 + Time33\newlineTotal time = 20s+30s+10s20 \, \text{s} + 30 \, \text{s} + 10 \, \text{s}Let's calculate the total time.\newlineTotal time = 20s+30s+10s=60s20 \, \text{s} + 30 \, \text{s} + 10 \, \text{s} = 60 \, \text{s}Finally, we calculate the average speed using the total distance and total time.\newlineAverage speed = Total distance / Total time\newlineAverage speed = 650m/60s650 \, \text{m} / 60 \, \text{s}Now, let's perform the calculation for the average speed.\newlineAverage speed = 650m/60s10.83m/s650 \, \text{m} / 60 \, \text{s} \approx 10.83 \, \text{m/s}

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