We want to factor the following expression: (x+1)^(2)-4y^(2) Which pattern can we use to factor the expression? U and V are either constant integers or single-variable expressions. Choose 1 answer: (A) (U+V)^(2) or (U-V)^(2) (B) (U+V)(U-V) (c) We can't use any of the patterns.

Recognize Pattern: Recognize the pattern in the expression. The expression (x+1)^(2)-4y^(2) resembles the difference of squares pattern, which is a^2 - b^2 = (a + b)(a - b).Identify a and b: Identify 'a' and 'b' in the pattern. In the expression (x+1)^(2)-4y^(2), 'a' is (x+1) and 'b' is 2y because (2y)^2 = 4y^2.Apply Difference of Squares: Apply the difference of squares pattern. Using the pattern a^2 - b^2 = (a + b)(a - b), we can factor the expression as follows: (x+1)^(2)-4y^(2) = [(x+1) + 2y] * [(x+1) - 2y].Write Factored Form: Write the factored form. The factored form of the expression is (x+1 + 2y)(x+1 - 2y).

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We want to factor the following expression:

(x+1)^(2)-4y^(2)
Which pattern can we use to factor the expression?

U and
V are either constant integers or single-variable expressions.
Choose 1 answer:
(A)
(U+V)^(2) or
(U-V)^(2)
(B)
(U+V)(U-V)
(c) We can't use any of the patterns.

We want to factor the following expression: $\newline$ $(x+1)^{2}-4 y^{2}$ $\newline$ Which pattern can we use to factor the expression? $\newline$ $U$ and $V$ are either constant integers or single-variable expressions. $\newline$ Choose $1$ answer: $\newline$ (A) $(U+V)^{2}$ or $(U-V)^{2}$ $\newline$ (B) $(U+V)(U-V)$ $\newline$ (C) We can't use any of the patterns.

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Algebra 1

Compare linear and exponential growth

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Q. We want to factor the following expression:

\newline

(x+1)^{2}-4 y^{2}

\newline

Which pattern can we use to factor the expression?

\newline

U

and

V

are either constant integers or single-variable expressions.

\newline

Choose

1

answer:

\newline

(A)

(U+V)^{2}

(U-V)^{2}

\newline

(B)

(U+V)(U-V)

\newline

Recognize Pattern: Recognize the pattern in the expression. $\newline$ The expression $(x+1)^{2}-4y^{2}$ resembles the difference of squares pattern, which is $a^{2} - b^{2} = (a + b)(a - b)$ .
Identify $a$ and $b$ : Identify ' $a$ ' and ' $b$ ' in the pattern. $\newline$ In the expression $(x+1)^{2}-4y^{2}$ , ' $a$ ' is $(x+1)$ and ' $b$ ' is $2y$ because $(2y)^{2} = 4y^{2}$ .
Apply Difference of Squares: Apply the difference of squares pattern. $\newline$ Using the pattern $a^2 - b^2 = (a + b)(a - b)$ , we can factor the expression as follows: $\newline$ $(x+1)^{2}-4y^{2} = [(x+1) + 2y] * [(x+1) - 2y]$ .
Write Factored Form: Write the factored form. $\newline$ The factored form of the expression is $(x+1 + 2y)(x+1 - 2y)$ .