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Under ideal conditions, Lemna minor (common duckweed) is a fastgrowing fern that can double its area every 2 days. Assume the growth is unrestricted, and that the duckweed initially covers 10 square centimeters 
(cm^(2)) in area. Which of the following functions, 
F, models the area (in 
cm^(2) ) the duckweed covers after 
d days?
Choose 1 answer:
(A)

F(d)=10(0.5)^((d)/(2))
(B) 
F(d)=2(10)^(d)
(c) 
F(d)=10(2)^(d)
(D) 
F(d)=10(2)^((d)/(2))

Under ideal conditions, Lemna minor (common duckweed) is a fastgrowing fern that can double its area every 22 days. Assume the growth is unrestricted, and that the duckweed initially covers 1010 square centimeters (cm2) \left(\mathrm{cm}^{2}\right) in area. Which of the following functions, F F , models the area (in cm2 \mathrm{cm}^{2} ) the duckweed covers after d d days?\newlineChoose 11 answer:\newline(A) F(d)=10(0.5)d2 F(d)=10(0.5)^{\frac{d}{2}} \newline(B) F(d)=2(10)d F(d)=2(10)^{d} \newline(C) F(d)=10(2)d F(d)=10(2)^{d} \newline(D) F(d)=10(2)d2 F(d)=10(2)^{\frac{d}{2}}

Full solution

Q. Under ideal conditions, Lemna minor (common duckweed) is a fastgrowing fern that can double its area every 22 days. Assume the growth is unrestricted, and that the duckweed initially covers 1010 square centimeters (cm2) \left(\mathrm{cm}^{2}\right) in area. Which of the following functions, F F , models the area (in cm2 \mathrm{cm}^{2} ) the duckweed covers after d d days?\newlineChoose 11 answer:\newline(A) F(d)=10(0.5)d2 F(d)=10(0.5)^{\frac{d}{2}} \newline(B) F(d)=2(10)d F(d)=2(10)^{d} \newline(C) F(d)=10(2)d F(d)=10(2)^{d} \newline(D) F(d)=10(2)d2 F(d)=10(2)^{\frac{d}{2}}
  1. Problem Understanding: Understand the problem.\newlineWe need to find a function that models the growth of the duckweed, which doubles in area every 22 days, starting from an initial area of 10cm210\,\text{cm}^2.
  2. Analyzing Answer Choices: Analyze the answer choices.\newline(A) F(d)=10(0.5)d2F(d)=10(0.5)^{\frac{d}{2}} suggests the area is halved every 22 days, which is the opposite of what we want.\newline(B) F(d)=2(10)dF(d)=2(10)^d suggests the area is multiplied by 1010 raised to the power of the number of days, which is not a doubling every 22 days.\newline(C) F(d)=10(2)dF(d)=10(2)^d suggests the area doubles every day, which is faster than the given rate.\newline(D) F(d)=10(2)d2F(d)=10(2)^{\frac{d}{2}} suggests the area is multiplied by 22 raised to the power of half the number of days, which could represent a doubling every 22 days.
  3. Determining the Correct Model: Determine the correct model by testing the doubling condition.\newlineWe know that after 22 days, the area should be double the initial area, which is 20cm220\,\text{cm}^2. Let's test option (D) since it seems to fit the doubling condition:\newlineF(2)=10(2)22=10(2)1=10×2=20cm2F(2) = 10(2)^{\frac{2}{2}} = 10(2)^1 = 10 \times 2 = 20\,\text{cm}^2.\newlineThis matches the condition that the duckweed doubles its area every 22 days.
  4. Confirming Other Options: Confirm that the other options do not match the doubling condition.\newline(A) F(2)=10(0.5)22=10(0.5)1=10×0.5=5 cm2F(2) = 10(0.5)^{\frac{2}{2}} = 10(0.5)^1 = 10 \times 0.5 = 5 \text{ cm}^2, which is incorrect.\newline(B) F(2)=2(10)2F(2) = 2(10)^2 is clearly much larger than 20 cm220 \text{ cm}^2, which is incorrect.\newline(C) F(2)=10(2)2=10×4=40 cm2F(2) = 10(2)^2 = 10 \times 4 = 40 \text{ cm}^2, which is also incorrect.
  5. Concluding the Correct Function: Conclude the correct function.\newlineBased on the analysis, the function that correctly models the growth of the duckweed is DD F(d)=10(2)d2F(d)=10(2)^{\frac{d}{2}}.

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