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The population of City 
Z was 50,000 in 1983 . From 1983 to 2013 , the population of City Z doubled every 5 years. Which of the following best models 
P, the population of City 
Z from 1983 to 
2013,t years after 1983 ?
Choose 1 answer:
(A) 
P=50,000(2)^((t)/(5))
(B) 
P=50,000(2)^(5pi)
(C) 
P=10,000 t+50,000
(D) 
P=20,000 t+50,000

The population of City Z was 5050,000000 in 19831983 . From 19831983 to 20132013, the population of City Z doubled every 55 years. Which of the following best models P P , the population of City Z from 19831983 to 2013,t 2013, t years after 19831983 ?\newlineChoose 11 answer:\newline(A) P=50,000(2)t5 P=50,000(2)^{\frac{t}{5}} \newline(B) P=50,000(2)Br P=50,000(2)^{\mathrm{Br}} \newline(C) P=10,000t+50,000 P=10,000 t+50,000 \newline(D) P=20,000t+50,000 P=20,000 t+50,000

Full solution

Q. The population of City Z was 5050,000000 in 19831983 . From 19831983 to 20132013, the population of City Z doubled every 55 years. Which of the following best models P P , the population of City Z from 19831983 to 2013,t 2013, t years after 19831983 ?\newlineChoose 11 answer:\newline(A) P=50,000(2)t5 P=50,000(2)^{\frac{t}{5}} \newline(B) P=50,000(2)Br P=50,000(2)^{\mathrm{Br}} \newline(C) P=10,000t+50,000 P=10,000 t+50,000 \newline(D) P=20,000t+50,000 P=20,000 t+50,000
  1. Understand the problem: Understand the problem.\newlineWe need to find a function that models the population of City Z, which doubles every 55 years from 19831983 to 20132013.
  2. Determine initial population: Determine the initial population and the rate of growth.\newlineThe initial population in 19831983 is given as 50,00050,000. The population doubles every 55 years, which means the growth rate is exponential.
  3. Translate into mathematical model: Translate the given information into a mathematical model.\newlineSince the population doubles every 55 years, we can use an exponential growth model of the form P=P0×2(t/k)P = P_0 \times 2^{(t/k)}, where P0P_0 is the initial population, tt is the time in years since 19831983, and kk is the number of years it takes for the population to double.
  4. Apply information to model: Apply the given information to the model.\newlineWe know P0=50,000P_0 = 50,000 and k=5k = 5. So, the model becomes P=50,000×2t/5P = 50,000 \times 2^{t/5}.
  5. Compare with answer choices: Compare the model with the given answer choices.\newlineThe model we derived, P=50,000×2t5P = 50,000 \times 2^{\frac{t}{5}}, matches answer choice (A).

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