The population of City Z was 50,000 in 1983 . From 1983 to 2013, the population of City Z doubled every 5 years. Which of the following best models P, the population of City Z from 1983 to 2013,t years after 1983 ?Choose 1 answer:(A) P=50,000(2)5t(B) P=50,000(2)Br(C) P=10,000t+50,000(D) P=20,000t+50,000
Q. The population of City Z was 50,000 in 1983 . From 1983 to 2013, the population of City Z doubled every 5 years. Which of the following best models P, the population of City Z from 1983 to 2013,t years after 1983 ?Choose 1 answer:(A) P=50,000(2)5t(B) P=50,000(2)Br(C) P=10,000t+50,000(D) P=20,000t+50,000
Understand the problem: Understand the problem.We need to find a function that models the population of City Z, which doubles every 5 years from 1983 to 2013.
Determine initial population: Determine the initial population and the rate of growth.The initial population in 1983 is given as 50,000. The population doubles every 5 years, which means the growth rate is exponential.
Translate into mathematical model: Translate the given information into a mathematical model.Since the population doubles every 5 years, we can use an exponential growth model of the form P=P0×2(t/k), where P0 is the initial population, t is the time in years since 1983, and k is the number of years it takes for the population to double.
Apply information to model: Apply the given information to the model.We know P0=50,000 and k=5. So, the model becomes P=50,000×2t/5.
Compare with answer choices: Compare the model with the given answer choices.The model we derived, P=50,000×25t, matches answer choice (A).
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