The equation of a circle is (x-9)^(2)+(y+8)^(2)=4. What are the center and radius of the circle? Choose 1 answer: (A) The center is (9,-8) and the radius is 2 . (B) The center is (-9,-8) and the radius is 2 . (C) The center is (9,8) and the radius is 2 . (D) The center is (9,-8) and the radius is 4 .

Identify Center of Circle: The equation of a circle is given in the standard form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius. We need to identify the values of h, k, and r from the given equation (x - 9)² + (y + 8)² = 4.Determine Center Coordinates: Comparing the given equation with the standard form, we can see that h = 9 and k = -8, because the center (h, k) comes from the terms (x - h) and (y - k). Therefore, the center of the circle is (9, -8).Find Radius of Circle: To find the radius r, we look at the right side of the equation, which is equal to r². Since r² = 4, we take the square root of both sides to find r. The square root of 4 is 2, so the radius of the circle is 2.

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The equation of a circle is
(x-9)^(2)+(y+8)^(2)=4. What are the center and radius of the circle?
Choose 1 answer:
(A) The center is
(9,-8) and the radius is 2 .
(B) The center is
(-9,-8) and the radius is 2 .
(C) The center is
(9,8) and the radius is 2 .
(D) The center is
(9,-8) and the radius is 4 .

The equation of a circle is $(x-9)^{2}+(y+8)^{2}=4$ . What are the center and radius of the circle? $\newline$ Choose $1$ answer: $\newline$ (A) The center is $(9,-8)$ and the radius is $2$ . $\newline$ (B) The center is $(-9,-8)$ and the radius is $2$ . $\newline$ (C) The center is $(9,8)$ and the radius is $2$ . $\newline$ (D) The center is $(9,-8)$ and the radius is $4$ .

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Algebra 1

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Q. The equation of a circle is

(x-9)^{2}+(y+8)^{2}=4

. What are the center and radius of the circle?

\newline

Choose

1

answer:

\newline

(A) The center is

(9,-8)

and the radius is

2

\newline

(B) The center is

(-9,-8)

and the radius is

2

\newline

(9,8)

and the radius is

2

\newline

(D) The center is

(9,-8)

and the radius is

4

Identify Center of Circle: The equation of a circle is given in the standard form $(x - h)^2 + (y - k)^2 = r^2$ , where $(h, k)$ is the center of the circle and $r$ is the radius. We need to identify the values of $h$ , $k$ , and $r$ from the given equation $(x - 9)^2 + (y + 8)^2 = 4$ .
Determine Center Coordinates: Comparing the given equation with the standard form, we can see that $h = 9$ and $k = -8$ , because the center $(h, k)$ comes from the terms $(x - h)$ and $(y - k)$ . Therefore, the center of the circle is $(9, -8)$ .
Find Radius of Circle: To find the radius $r$ , we look at the right side of the equation, which is equal to $r^2$ . Since $r^2 = 4$ , we take the square root of both sides to find $r$ . The square root of $4$ is $2$ , so the radius of the circle is $2$ .